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Normal Distribution and Z-Scores in Applied Statistics: Calculating Probabilities, Assignments of Statistics

How to evaluate normally distributed random variables using z-scores and the standard normal distribution. It includes examples and instructions on how to calculate z-scores and find probabilities using z-tables and a ti-83 calculator. The document also covers reverse engineering to find the value of a variable corresponding to a given probability.

Typology: Assignments

Pre 2010

Uploaded on 08/18/2009

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MATH 170 - Applied Statistics
Section 7.6 Normal Distribution Part II
1Z-Scores and the Normal Distribution
Previously we talked about calculating:
Probabilities of standard normal random variables using:
z-tables, or
TI-83
Probabilities of normally distributed random variables with mean µand standard deviation
σusing:
TI-83 ... Only!!!
Now we’ll discuss how to evaluate normally distributed random variables with mean µand stan-
dard deviation σusing the z-tables. The key is:
Convert from
a probability in terms of the original variable (P(axb))
to
a probability in terms of it’s z-scores (P(czd))
How do we figure out what the cand dare in P(axb) = P(czd)? First we must recall the
formula for calculating a z-score:
The z-score associated with the value a, where the random variable is normally distributed with mean
µand standard deviation σis the number of standard deviations ais away from the mean
and is computed by
z=
pf3

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MATH 170 - Applied Statistics Section 7.6 Normal Distribution – Part II

1 Z-Scores and the Normal Distribution

Previously we talked about calculating:

  • Probabilities of standard normal random variables using:
    • z-tables, or
    • TI-
  • Probabilities of normally distributed random variables with mean μ and standard deviation σ using: - TI-83 ... Only!!!

Now we’ll discuss how to evaluate normally distributed random variables with mean μ and stan- dard deviation σ using the z-tables. The key is:

Convert from a probability in terms of the original variable (P (a ≤ x ≤ b)) to a probability in terms of it’s z-scores (P (c ≤ z ≤ d))

How do we figure out what the c and d are in P (a ≤ x ≤ b) = P (c ≤ z ≤ d)? First we must recall the formula for calculating a z-score:

The z-score associated with the value a, where the random variable is normally distributed with mean μ and standard deviation σ is the number of standard deviations a is away from the mean and is computed by

z =

Thus, if x is normally distributed with mean μ and standard deviation σ

P (a ≤ x ≤ b) = P (z-score assoc. with a ≤ z ≤ z-score assoc. with b)

= P

( a − μ σ

≤ z ≤

c − μ σ

)

Example 1 Suppose y is the weight of a randomly chosen newborn baby. Assume that the weight of newborns is normally distributed with a mean of 118 ounces (i.e. 7 pounds and 6 ounces) and a standard deviation of 24 ounces. For the following questions, convert to corresponding z-scores and use the standard normal distribution to answer the following questions. Show your z-score calculations, include a probability statement with your work and a sketch of the appropriate normal curves and the shaded area corresponding to the probability!

  1. What is the probability that the newborn weighs less than 82 ounces?
  2. What is the probability that the newborn weighs between 94 and 166 ounces?
  3. What is the probability that the newborn weighs more than 124 ounces?