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mole to mole conversions, mole to mass conversions, mass to mass and volume conversions and stoichiometry calculations problems with answer key are listed in this exercise
Typology: Exercises
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Define the following terms:
(Mole-Mole Conversions)
3 SiO 2 + 4 Al 3 Si + 2 Al 2 O 3 a. If 6.0 moles of SiO 2 react, how many moles of: i. Al react? ii. Si are produced? iii. Al 2 O 3 are produced?
b. If 2.5 moles of Al 2 O 3 are produced, how many moles of: i. Al react? ii. SiO 2 react?
(Mole-Mass / Mass-Mole Conversions)
a) If 15.0g of N 2 O 4 was produced, how many moles of O 2 were required?
15.0g N 2 O 4 1 mol N 2 O 4 2 mol O 2 92.0g N 2 O 4 1 mol N 2 O 4
= 0.326 mol O (^2)
b) If 4.0x10-3^ moles of oxygen reacted, how many grams of N 2 were needed?
4.0x10-^3 mol O 2 1 mol N 2 28.0g N 2 2 mol O 2 1 mol N 2
= 5.6x10 -2^ g N (^2)
3.50g AgNO 3 1 mol AgNO 3 1 mol Cu 169.9g AgNO 3 2 mol AgNO 3
= 1.03x10 -2^ mol Cu
36.92g Cu 1 mol Cu 2 mol Ag 107.9g Ag 63.5g Cu 1 mol Cu 1 mol Ag
= 125g Ag
165.7g Al 2 (SO 4 ) 3 1 mol Al 2 (SO 4 ) 3 2 mol Al(OH) 3 78.0g Al(OH) 3 342.3g Al 2 (SO 4 ) 3 1 mol Al 2 (SO 4 ) 3
= 75.5g Al(OH) 3
b. How many grams of calcium hydroxide are needed to form 6.35g of calcium sulphate?
6.35g CaSO 4 1 mol CaSO 4 3 mol Ca(OH) 2 74.1g Ca(OH) (^2) 136.2g CaSO 4 3 mol CaSO 4 1 mol Ca(OH) (^2)
= 3.45g Ca(OH) 2
(Mass- Volume/ Volume-Volume Conversions)
a. What mass of water is required to react with 15.5 L of Nitrogen dioxide? b. What volume of Nitrogen monoxide would be produced from 100.0 g of water? c. If 42.0 L of NO (g) is produced, what volume of NO 2 (g) reacted?
3 O2 (g) + 4 Fe (^) (s) 2 Fe 2 O3 (s)
a. What volume of Oxygen gas would be required to produce 16.0 g of Fe 2 O 3? b. What mass of Iron would be required to react with 10.0 L of O 2 gas?
2Al + 6HNO 3 2Al(HNO 3 ) 3 + 3H 2 5.4g Al 1mol Al 6 mol HNO 3 27.0g Al 2 mol Al = 0.60 molsHNO 3
[HNO 3 ] = # mols ÷ volume So, Volume = mols ÷ [HNO 3 ] =0.60mol ÷2M = 0.3 L (x 1000)= 3.0 x10 2 mL HNO (^3)
You calculate that using a certain amount of beryllium and hydrochloric acid you can produce 10.7g of beryllium chloride. You perform the experiment and only collect 4.5g What is the percent yield for the reaction? 42% yield
FeBr 2 + 2 KCl FeCl 2 + 2 KBr a) What is the theoretical yield of iron (II) chloride if 34.00 grams of iron (II) bromide was used in the reaction with excess potassium chloride? 20.00g FeCl (^2) b) What is the percent yield of iron (II) chloride if the actual yield is 4.00 grams? 20.0% yield
5C(s) + 2SO2(g) CS2(s) + 4CO2(g)