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Chemistry Homework: Nomenclature and Ionic Compounds, Exercises of Chemistry

A set of chemistry homework questions focusing on nomenclature and the formation of ionic compounds. The questions involve identifying the type of structure, writing formulas for compounds, and naming various ionic compounds. Students are expected to have a solid understanding of electron configurations, ionic charges, and the rules for naming ionic compounds.

What you will learn

  • What is the formula of a compound with lithium for an element with the given electronic configuration?
  • Write the formula of a compound with sulfate for an element with the given electronic configuration.
  • Which crystallize in the same type of structure with the lowest lattice energy?

Typology: Exercises

2021/2022

Uploaded on 09/12/2022

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Version 001 HW11-Nomenclature sparks (52100) 1
This print-out should have 13 questions.
Multiple-choice questions may continue on
the next column or page find all choices
before answering.
ChemPrin3e T02 60
001 10.0 points
If the following crystallize in the same type of
structure, which has the lowest lattice energy?
1. CaO
2. BaS correct
3. BaO
4. SrS
5. SrO
Explanation:
Lowest charge densities due to larger size.
ChemPrin3e T02 10
002 10.0 points
An element E has the electronic configuration
[Ne] 3s23p1. Write the formula of its com-
pound with sulfate.
1. E2(SO4)
2. E(SO4)3
3. E3(SO4)
4. E(SO4)2
5. E3(SO4)2
6. E2(SO4)3correct
Explanation:
E is aluminum; since it has three valence
electrons it forms a +3 ion isoelectronic with
Ne.
ChemPrin3e T02 76
003 10.0 points
An element E has the electronic configura-
tion 1s22s22p4. What is the formula of its
compound with lithium?
1. LiE
2. Li4E
3. Li2Ecorrect
4. LiE2
Explanation:
E is oxygen; since it has six valence elec-
trons, it forms a 2ion isoelectronic with
Ne.
Mlib 07 0233
004 10.0 points
Which of the following is the best represen-
tation of the compound calcium sulfide?
1. Ca2+ ,2S
b
b
b
b
b
b
b
b
2. None is appropriate because calcium sul-
fide is a covalent compound.
3. 2 Ca+,S
b
b
b
b
b
b
b
b
2
4. Ca+,S
b
b
b
b
b
b
b
b
5. 3 Ca2+ ,2S
b
b
b
b
b
b
b
b
3
6. Ca2+ ,S
b
b
b
b
b
b
b
b
2
correct
Explanation:
The metal loses all of its outer (valence)
electrons; the non-metal gains sufficient elec-
trons to form an octet. The ratio of the
negative and positive ions is chosen so there
is no overall charge.
Sparks ionic name 005
005 10.0 points
Name the compound CaBr2.
1. calcium diboride
pf3
pf4

Partial preview of the text

Download Chemistry Homework: Nomenclature and Ionic Compounds and more Exercises Chemistry in PDF only on Docsity!

This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering.

ChemPrin3e T02 60 001 10.0 points If the following crystallize in the same type of structure, which has the lowest lattice energy?

  1. CaO
  2. BaS correct
  3. BaO
  4. SrS
  5. SrO

Explanation: Lowest charge densities due to larger size.

ChemPrin3e T02 10 002 10.0 points An element E has the electronic configuration [Ne] 3s^2 3 p^1. Write the formula of its com- pound with sulfate.

  1. E 2 (SO 4 )
  2. E(SO 4 ) 3
  3. E 3 (SO 4 )
  4. E(SO 4 ) 2
  5. E 3 (SO 4 ) 2
  6. E 2 (SO 4 ) 3 correct

Explanation: E is aluminum; since it has three valence electrons it forms a +3 ion isoelectronic with Ne.

ChemPrin3e T02 76 003 10.0 points An element E has the electronic configura- tion 1s^2 2 s^2 2 p^4. What is the formula of its

compound with lithium?

  1. LiE
  2. Li 4 E
  3. Li 2 E correct
  4. LiE 2

Explanation: E is oxygen; since it has six valence elec- trons, it forms a 2− ion isoelectronic with Ne.

Mlib 07 0233 004 10.0 points

Which of the following is the best represen- tation of the compound calcium sulfide?

  1. Ca2+^ , 2

[

S

bb

bb bb bb

]−

  1. None is appropriate because calcium sul- fide is a covalent compound.
  2. 2 Ca+^ ,

[

S bb

bb bb bb

] 2 −

  1. Ca+^ ,

[

S

bb bb bb bb

]−

  1. 3 Ca2+^ , 2

[

S

bb bb bb bb

] 3 −

  1. Ca2+^ ,

[

S bb

bb bb bb

] 2 −

correct

Explanation: The metal loses all of its outer (valence) electrons; the non-metal gains sufficient elec- trons to form an octet. The ratio of the negative and positive ions is chosen so there is no overall charge.

Sparks ionic name 005 005 10.0 points Name the compound CaBr 2.

  1. calcium diboride
  1. calcium dibromide
  2. calcium(II) bromide
  3. calcium boride
  4. calcium bromide correct

Explanation:

Sparks ionic form 002 006 10.0 points Choose the formula for the compound magne- sium sulfide.

  1. MgS 2
  2. MgS correct
  3. Mg 2 S 3
  4. Mg 2 S

Explanation:

Name Formula Match 007 10.0 points Choose the pair of names and formulae that do not match.

  1. SnCl 4 : tin(V) chloride correct
  2. MgSO 4 : magnesium sulfate
  3. SiCl 4 : silicon tetrachloride
  4. N 2 O 3 : dinitrogen trioxide
  5. KNO 3 : potassium nitrate

Explanation:

ChemPrin3e D 05 008 10.0 points What is the formula of carbon disulfide?

  1. C 3 S 2
  2. None of these
  3. CS 2 correct

4. CS 3

5. CS

6. C 2 S 3

Explanation: Using the molecular naming system, there is no prefix on carbon implying one carbon atom per molecule and the ‘di’ prefix on ‘sul- fide’ implies there are two sulfur atoms. The formula is CS 2.

ChemPrin3e D 24c 009 10.0 points Name the compound CaC 2 O 4.

  1. cadmium carbonate
  2. cadmium carboxide
  3. calcium oxalate correct
  4. calcium carboxide
  5. calcium carbonate
  6. cadmium oxalate Explanation: To name an ionic compound, identify and write the cation name first, then the anion name. If the cation is a metal that forms more than one possible ion, place a roman numeral in brackets immediately after the cation name to indicate the charge on the cation.

Mlib 01 2039 010 10.0 points Give the formula for sodium nitrate.

  1. Na(NO) 3
  2. NaNO 3 correct
  3. Na(NO 3 ) 2
  4. Na 3 NO 3 Explanation:

Explanation:

Na b gives up an electron to form the Na

cation and b bb

b b b S acquires two electrons to

form the bb bb

b b bb

S

2 − anion:

Na b+ Na b+ b bb

b b Sb −→

Na

  • Na

  • bb bb

b b Sbb

2 − −→ Na 2 S