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Understanding Constant Rate of Change and Direct Variation from a Linear Graph, Lecture notes of Linear Algebra

An explanation of constant rate of change and direct variation through the analysis of a linear graph representing the relationship between time and distance of a car traveling at a constant speed. Students are encouraged to find the rate of change between any two points on the graph and explore the concept of proportionality in linear relationships.

What you will learn

  • What is the rate of change between two specific points on the graph?
  • What is the meaning of a constant rate of change in the context of this graph?
  • How does the rate of change vary between different points on the graph?

Typology: Lecture notes

2021/2022

Uploaded on 09/12/2022

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Unit8Day4
ConstantRateofChange
anddirectvariation
EssentialQuestion:
Whatdoesalineargraphthatisa
straightlinetellyouabouttherateof
change?
y
x
1
2
4
3
6
5
time(hr)
distance(mi)
100
200
300
400
(1,55)
(2,110)
(3,165)
(4,220)
TravelTIme
Thegraphshowtherelationship
betweentimeanddistanceofacar
traveling55milesperhour.
A.Chooseanytwopointsonthe
graphandfindtherateofchange.
B.Repeatpartawithdifferentpoints.
Whatistherateofchange
C.Whatdoyounoticeabouttherateofchangebetweenany
twopoints?
ThegraphfortheTravelTimeisastraightline.
Relationshipsthathavestraightlinegraphsarecalled
linearrelationships
.Noticethatasthetimeinhours
increaseby1,thedistanceincreasesby55.
Time(hr)
0
1
2
3
4
Distance(mi)
0
55
110
165
220
changeindistance
=
55
or55mph
changeintime1
Therateofchangebetweenanytwopointsinalinear
relationshipisthesameorconstant.Wedescribethisasa
constantrateofchange
.
ConstantRateofChange
ConstantRateofChange
NotaConstant
RateofChange
Somelinearrelationshipsareproportional.Iftheratiosareequal,
thelinearrelationshipisproportional.Iftheratiosarenotequal,
thelinearrelationshipisnonproportional.
1
2
3
4
4
8
12
16
Costofparkingy

4

8

12

16

Numberofpeoplex1234
Theratiosareequal,sothisisproportional.

=4
=4
=4
=4
Costofticketsy

13

22

31

40

Numberofpeoplex1234
Theratiosarenotequal,sothisisnonproportional.
=13
=11
=11.3
=10
Numberofpeoplex
1
2
3
4
Costofticketsy
13
22
31
40
Aspecialtypeoflinearequationthatdescribesconstantrateof
changeiscalleda
directvariation
.Thisgraphalwayspasses
throughtheorigin(0,0)andisaproportionalrelationship.
The
constantofvariation
is
k
intheequation
y=kx
.Youcan
find
k
by
k=.
Youcanuseanypointontheline,oronatable,
orfromawordproblemtofindthevalueof
k
.

y
x
pf2

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Download Understanding Constant Rate of Change and Direct Variation from a Linear Graph and more Lecture notes Linear Algebra in PDF only on Docsity!

Unit 8 Day 4

Constant Rate of Change

and direct variation

Essential Question:

What does a linear graph that is a

straight line tell you about the rate of

change?

y x 1 2 3 456 time (hr) distance (mi) 100 200 300 400 (1, 55)^ (2,^ 110) (3, (4,165)^ 220) Travel TIme The graph show the relationship between time and distance of a car traveling 55 miles per hour. A. Choose any two points on the graph and find the rate of change. B. Repeat part a with different points. What is the rate of change C. What do you notice about the rate of change between any two points? The graph for the Travel Time is a straight line. Relationships that have straightline graphs are called linear relationships. Notice that as the time in hours increase by 1, the distance increases by 55. Time (hr) 0 1 2 3 4 Distance (mi) 0 55 110 165 220 change change in distancein time = 551 or 55 mph The rate of change between any two points in a linear relationship is the same or constant. We describe this as a constant rate of change. Constant Rate of Change Constant Rate of Change Not Rate^ a ofConstant Change Some linear relationships are proportional. If the ratios are equal, the linear relationship is proportional. If the ratios are not equal, the linear relationship is nonproportional. number of people x (^1 2 3 ) cost of parking y (^4 8 12 ) Number^ Cost^ of of^ parking people^ yx^41 82 123
The ratios are equal, so this is proportional. = 4 = 4 = 4 = 4 Cost of tickets y 13 22 31 40 Number of people x 1 2 3 4 The ratios are not equal, so this is nonproportional. Number of people x (^1 2 3 4) = 13 = (^11) =11.3 = Cost of tickets y (^13 22 31 )

A special type of linear equation that describes constant rate of

change is called a direct variation. This graph always passes

through the origin (0, 0) and is a proportional relationship.

The constant of variation is k in the equation y = kx. You can

find k by k =. You can use any point on the line, or on a table,

or from a word problem to find the value of k.

y x

Let's try find the direct variation in each situation:

information (mb) time (s) x y 2.5 10 3.75 15 10 40

y = kx k = y k =

x

replace k with. y = x

The cost of cheese varies directly with the number of pounds

bought. Suppose 2 pounds of cheese cost $8.40. Write an

equation that could be used to find the unit cost of cheese.

y = kx k =

Find the cost of 3.5 pounds of cheese.

y

x