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Kyle Mitlananan £5 #3 Monday, February 27, 2023 2:07 PM Problem 3.61 A rigid tank initially contains 1.4 kg saturated liquid water at 200°C. At this state, 25 percent of the volume is occupied by water and the rest by air. Now heat is supplied to the water until the tank contains saturated vapor only. Determine (a) the volume of the tank, (b) the final temperature and pressure, and (c) the internal energy change of the water. AT, = 2o0% b. V2 Vn C. V) = 0.001152 1?/Ky r U, = 850.46 KI/Hy = oa |: Vz MV, > 0046 3/Ky =L4X -ooll5 7 = -g0lblm? 1, > 374+ ( 373.95 -370) .004b- 0 483 | :003l06- .004453 Vaz WU) = 4X .oo\bl p= ro44 + Cr 064 “Atoll 0046 004953 -J03|0b~ 004463 B= 21239. 44 Kp | Problem 3.63 The spring-loaded piston—cylinder device shown in Fig. P3—63 is filled with 0.5 kg of water vapor that is initially at 4 MPa and 400°C. Initially, the spring exerts no force against the piston. The spring constant in the spring force relation F = kx is k = 0.9 kN/cm and the piston diameter is D = 20 cm. The water now undergoes a process until its volume is one-half of the original volume. Calculate the final temperature and the specific enthalpy of the water. Uy, = 2230.| td QolS- ?- 2230-1) (0046 100.4453 = 2.184.123 Ki/Hy Au 27" Cu, -u,) 1.4) ( 9,184,123 - 950-46) Au= |974.)2 L— Spring | Steam a FIGURE P3-63 DF: B-F = Ky) K= a Kum A= YMpA = KOA -Ax) = dom Te une = Kry 7 Supt htated luble at 24 Mpa and T= Vat ALA-Y = KM Ciy-v)) Y= OF343NY/ Ky ys CEES - 030715 A Pr- Wr? = 400.5) 2 400-5) 036 71S - 27343) dia = aL C4-vi) [tar] C PrP H= Ko (yy) ' P,= 2.326 MPA B + aig. (2324 - 2080 ) (223.45- 219-54) T Oo Vy= -08604y ny he > 443.55 Ki/Ky hy 2 24o1 Ky /hy My > UW -Up = -O36715- -coll4o Vy-VvF OBLoqy- .00 [140 X7> UG Y hy, « he + Xo ( hg- ht) aui3.55 + UL LG0I- 143-55) Problem 3.75 A 1-m:tank containing air at 10°C and 350 kPa is connected through a valve to another tank containing 3 kg of air at 35°C and 150 kPa. Now the valve is opened, and the entire system is allowed to reach thermal equilibrium with the surroundings, which are at 20°C. Determine the volume of the second tank and the final equilibrium pressure of air. R= 267 Mg. 1 Vy My xR x Ty A, = 3x .297x (273135) See ee 150 Va= | #7 m3 M, = Ax, XT = 350 XI 28T x (273 410) M= 43042 Ky f - Cmitm) xR x5 V, TV = (344-3042) x 23 420 lt 176792 P37 222.05 KPa Problem 3.84 Determine the specific volume of superheated water vapor at 15 MPa and 350°C using (a) the ideal-gas equation, (b) the generalized compressibility chart, and (c) the steam tables. Also determine the error involved in the first two cases. | P= mAT b. (edued plessule C. Ve -o1I49| W/ity (\ xlooo)-V = .U6IS x C273 1350) 15,o90-V = 61S x 623 IS/22.\2 = 679 Seto ( ott oua ISa00V__ = 287.5145 01149] (ve 0141 4g n3/Hg } (tducza WeMPelable 66-74 623/47 = .9¢3 V= 65x -OlMI? V2 -oldUb 13/Ky } X loo Zclor ( 01046 ~-oll4gi \x loo “OU g| -003|06 - .004953 } 
