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Material Type: Assignment; Professor: Buchanan; Class: Calculus 1; Subject: Mathematics; University: Millersville University of Pennsylvania; Term: Unknown 2008;
Typology: Assignments
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MATH 161 Calculus I
J. Robert Buchanan
Department of Mathematics
Summer 2008
We have seen that if f (x) ≥ 0 and continuous on the interval [a, b] the exact area under the graph of f (x), above the x-axis, and between x = a and x = b is
A = lim n→∞
n= 1
f (ci )∆x.
Remark: the limit makes sense even when f (x) < 0, but the value of the limit cannot be strictly interpreted as area.
Definition For any function f defined on [a, b], the definite integral of f from a to b is ∫ (^) b
a
f (x) dx = (^) nlim→∞
n= 1
f (ci )∆x,
whenever the limit exists and is the same for any choice of evaluation points c 1 , c 2 ,... , cn. When the limit exists we say that f is integrable on [a, b].
∫ (^) b
a
f (x) dx
a: is called the lower limit of integration. b: is called the upper limit of integration. f (x): is called the integrand. dx: denotes the variable of integration.
Example Use midpoint evaluation to approximate the definite integral ∫ (^3)
0
x^2 + 1 dx
n An 10 5. 6491 50 5. 6525 100 5. 6526
Example Use the limit of a Riemann sum to compute the following definite integral exactly. ∫ (^3)
0
(x^2 + 1 ) dx
a b c x
y
A 1
A 2
∫ (^) c
a
f (x) dx = A 1 − A 2
Example Express as a definite integral the total area between y = 6 x − x^2 and the x-axis on the interval [ 0 , 6 ].
Example An object moving along a straight line has velocity function v (t) = cos t. If the object starts at position 0, (^1) determine the total distance the object travels between t = 0 and t = 3 π/2, and (^2) determine the net distance the object travels between t = 0 and t = 3 π/2.
Theorem If f is continuous on [a, b] then f is integrable on [a, b].
Remark: in fact f remains integrable even when it has a finite number of jump or removable discontinuities.
Theorem If f and g are integrable on [a, b], then (^1) for any constants c and d, ∫ (^) b
a
(cf (x) + dg(x)) dx = c
∫ (^) b
a
f (x) dx + d
∫ (^) b
a
g(x) dx,
(^2) for any c in interval [a, b], ∫ (^) b
a
f (x) dx =
∫ (^) c
a
f (x) dx +
∫ (^) b
c
f (x) dx.
The following properties also hold for definite integrals: ∫ (^) b
a
f (x) dx = −
∫ (^) a
b
f (x) dx ∫ (^) a
a
f (x) dx = 0 if f (a) is defined.
Example
Suppose f (x) =
−√x if x < 0 4 − x^2 if 0 ≤ x ≤ 2 and evaluate ∫ (^2)
− 2
f (x) dx.
y
Suppose f is continuous on [a, b] and {x 0 , x 1 ,... , xn} is a regular partition of [a, b], then the average of {f (x 1 ), f (x 2 ),... , f (xn)} is
1 n
∑^ n
i= 1
f (xi ) =
n
∑^ n
i= 1
f (xi )
b − a n
n b − a
b − a
∑^ n
i= 1
f (xi )∆x
n^ lim→∞
n
∑^ n
i= 1
f (xi ) = (^) nlim→∞
b − a
∑^ n
i= 1
f (xi )∆x
favg =
b − a
∫ (^) b
a
f (x) dx.
Example Estimate the average value of cos x on the interval [ 0 , π/ 2 ].
0.5 1.0 1. x
y