Texas Irrigator Section 3 Final Exam Review Questions and Answers, Exams of Water Resources Planning and Management

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Texas Irrigator Section 3

Final Exam Review Questions

and Answers 100%Pass

David Mungai [Date] [Course title]

Texas Irrigator Section 3 Final Exam

Review Questions and Answers

100%Pass

An engineer scale is: a). A measuring device that has measurements as a given number of feet per inch. b). A measuring device that has measurements as a given number of inches per foot. c). A measuring device in which a fraction of an inch equals 1 foot. d). None of the above. - Answer>> a). A measuring device that has measurements as a given number of feet per inch. In calculating the available water capacity, pressure loss through the water meter should not exceed what percentage of the minimum static water pressure available? a). 5 b). 15 c). 25 d). 10 - Answer>> d). 10 The maximum water flow through the water meter should not exceed: a). 75% of the safe flow of the meter. b). 50% of the safe flow of the meter. c). 25% of the safe flow of the meter. d). 10% of the safe flow of the meter. - Answer>> a). 75% of the safe flow of the meter What is the maximum acceptable velocity of the water flow through the copper service line? a). 10 fps b). 9 psi

d). Half of the radius of a given head - Answer>> b). Diameter of the spray of a given head Head to head spacing on all sprinkler heads is considered? a). 70% spacing b). 40% spacing c). 10% spacing d). 50% spacing - Answer>> d). 50% spacing What would 60% spacing be on a 12' spray head? a). 14.40 feet b). 7.2 feet c). 10 feet d). 12 feet - Answer>> a). 14.40 feet (Use the diameter of the head which is 24' (12'x2) (24' diameter x .60 = 14.40)) What are the most common spacing patterns? a). Rectangular spacing b). Square spacing c). Triangular spacing d). B & C - Answer>> d). B & C What is the row spacing, using triangular spacing, when the head spacing is 15 feet? a). 18 feet b). 13 feet c). 15 feet d). 14 feet - Answer>> b). 13 feet (15' x .866 = 12.99', rounded to 13') If you want the average precipitation rate for an area, which method would work? a). Single head method b). Triangular spacing method

c). Specific area method d). Total area method - Answer>> d). Total area method What would the average precipitation rate be in an area of 700 square feet with total GPM of 6? a). .83 in/hr b). .50 in/hr c). 4.00 in/hr d). .75 in/hr - Answer>> a). .83 in/hr (Use the total area formula for precipitation: 96.3 X Total GPM/Total Area 96.3 x 6/700 = = 577.8/700 = .83"/hr) What would the precipitation rate in a specific area (of a larger area) with 4 fulls, each 8 GPM, and the head spacing and row spacing are each 33 feet? a). 1. b).. c).. d). .71 - Answer>> d).. (Use the specific area formula for precipitation: 96.3 X GPM (1 Full Head) / Head Spacing x Row Spacing 96.3 x 8/33' x 33' = 770.4/1089 = .71"/hr What is the precipitation rate in an area that has triangular spacing with each full head being 3 GPM and head spacing of 28 feet? a). 1.07 in/hr b). .90 in/hr c). .43 in/hr d). 1.21 in/hr - Answer>> c). .43 in/hr Use the triangular area formula for precipitation: 96.3 X GPM (1 Full Head) / (Head Spacing)^2 x.

b). Flood Bubblers c). Spray heads d). Rotary heads - Answer>> d). Rotary heads For a small turf area measuring 20' by 10', what type of sprinkler heads would work best? a). Spray heads b). Flood bubblers c). Single stream rotary heads d). None of the above - Answer>> a). Spray heads What type of sprinkler heads would be used if you are watering a narrow parkway with turf measuring 4' by 100'? a). Spray heads b). Flood bubblers c). Rotary heads d). None of the above - Answer>> a). Spray heads What type of irrigation would be used if you are watering a narrow parkway with turf measuring less than 48 inches by 60 feet? a). Spray heads b). Flood bubblers c). Rotary heads d). Drip Irrigation - Answer>> d). Drip Irrigation A shrub bed with staggered plants is best watered with: a). Drip Irrigation b). Spray heads c). Flood bubblers d). Rotary heads - Answer>> a). Drip Irrigation What would the head spacing be if the turf distance was 134 feet, using 15' spray heads? a). 13.5 feet b). 15 feet

c). 13 feet d). 14.9 feet - Answer>> d). 14.9 feet 134' / 15' = 8.93, round up to the next highest whole number of 9 134' / 9' = 14.89' rounded to 14.9' What is an important design feature that will result in an irrigation system operating more efficiently? a). Use all spray heads b). 100 % Coverage c). Uniformity d). Use rotary heads - Answer>> c). Uniformity What would the head spacing be if the landscape distance was 169 feet, using a 35' rotary head? a). 29 feet b). 27.5feet c). 35 feet d). 33.8 feet - Answer>> d). 33.8 feet 169' / 35' = 4.83, round up to the next highest whole number of 5 169' / 5' = 33.8' Diffusion of spray and rotary sprinkler heads should not exceed: a). 10 - 15% b). 5 - 10% c). 20 - 25% d). 25 - 30% - Answer>> d). 25 - 30% Adjustable spray heads are best used in areas that have: a). areas with slopes. b). odd and varying shaped areas. c). small shrub beds. d). large turf areas. - Answer>> b). odd and varying shaped areas. Sprinkler heads on a slope should be installed:

The service line would be defined as what? a). Piping from the city main to the water meter b). Piping from the backflow device to the zone valves c). Piping from the water meter to the backflow device d). A & C - Answer>> d). A & C Piping from the backflow device to the zone valves is considered: a). The main line. b). The lateral line. c). The service line. d). The city main. - Answer>> a). The main line. A loop main line is a main line that supplies water from: a). Only one main source. b). More than two sources. c). Two backflow devices. d). Two or more directions. - Answer>> d). Two or more directions. Lateral lines are located: a). Downstream from the zone valves. b). Upstream from the meter. c). Between the backflow and zone valves. d). Before the meter. - Answer>> a). Downstream from the zone valves. What do you need to size pipe? a). The size of the pipe downstream from the section you are sizing. b). The size of the zone valve feeding the section you are sizing. c). The GPM flowing through the pipe and the correct velocity and friction loss chart. d). The rigidity of the pipe. - Answer>> c). The GPM flowing through the pipe and the correct velocity and friction loss chart.

The maximum velocity in PVC and poly pipe (to prevent damaging pipe or other components of the irrigation system) should be? a). 9 FPS b). 7.5 FPS c). 5 FPS d). 5 - 7.5 FPS - Answer>> c). 5 FPS What pipe has a recommended maximum velocity of 9 FPS? a). Schedule 40 PVC pipe b). Class pipe c). Poly pipe d). Copper pipe - Answer>> d). Copper pipe Using the Class 200 velocity and friction loss chart, what would be the correct size pipe if running 12 and 32 GPM, respectively? a). 1" & 2" b). ¾" & 1 ¼" c). 1" & 1 ½" d). ½" & ¾" - Answer>> c). 1" & 1 ½" The correct size of Class 200 pipe flowing 10 GPM is ¾", however what could happen if the pipe run was extremely long? a). There could be an unacceptable amount of friction loss, therefore the pipe size may need to be increased. b). The water would take too much time reaching the landscape. c). Class 315 piping would have to be used. d). Copper piping would have to be used. - Answer>> a). There could be an unacceptable amount of friction loss, therefore the pipe size may need to be increased. What is the maximum FPS when sizing backflow units? a). 9 FPS b). 7.5 FPS

What should be the maximum variation in head pressure from the first to the last head in a zonea? a). 5% b). 10 PSI c). 5 PSI d). 10% difference - Answer>> d). 10% difference How many minutes would you run an irrigation zone (per watering event) if the plant requirement is .09 per day, the precipitation rate of this zone is .75, and watering is allowed only 3 days a week? a). 30 minutes b). 7 minutes c). 17 minutes d). 44 minutes - Answer>> c). 17 minutes Use the Run Time formula (memorize this formula): RT = R/PR x 60 where: RT is Run Time (Minutes) R is Plant Requirement PR is Precipitation Rate .09 x 7 = .63 plant requirement per week .63/.75 x 60 = 50.40 minutes per week 50.40 ÷ 3 = 17 minutes rounded per week If the north and south sides of a building are both 70 feet in length, what is the length of the east and west sides if the total square footage is 2800? a). 30 feet b). 60 feet c). 50 feet d). 40 feet - Answer>> d). 40 feet 2800' area ÷ 70' = 40' An irrigation system was designed with 500 rotary heads, each throwing 8 GPM each at 40 PSI for optimum watering. The system runs a total of 3500 minutes a year. After a year of operation, there was a mistake with the design and each head had been operating at 50 PSI which increased the GPM of each

head by 25%. How many gallons of water have been wasted during that year and how much money has been lost if water runs $6 dollars per 1000 gallons? a). 3,500,000 gallons wasted, $21,000 lost b). 14,000,000 gallons wasted, $84,000 lost c). 35,000 gallons wasted, $210 lost d). 17,500,000 gallons wasted, $105,000 lost - Answer>> a). 3,500,000 gallons wasted, $21,000 lost 8 GPM x .25 = 2 GPM excess 2 GPM x 500 Heads = 1000 GPM excess per minute 1000 GPM x 3500 Minute/year = 3,500,000 Gallons wasted 3500,000/1000 x $6 = $21,000 lost For exercises 54 to 59, use the following information: Using graph paper and a 1" = 20' scale on an engineer scale, draw the 70' front side of a house facing south. The back of the 3500 square foot house is also 70'. Complete the house design and follow the instructions below to draw the site accurately around the house. Assume that north is pointing straight up on your graph paper. Note: Remember, use line-of-site measurements from the house when drawing the dimensions below. For example, for #1 below, you would measure 20' directly from the NW corner of the house, following the same line as the west side of the house.

1. The northern property line is 20' from the NW corner of the house 2. The north property line is 25' from the NE corner of the house.
2. The east property line is 15' from the NE corner of the house.
3. The east property line is 10' from the SE corner of the house.
4. The south property line is - Answer>> The sides of the home were calculated using the following: 3500 sq ft home / 70' width = 50' What is the length of the south property line? a). 93'

d). 24' - Answer>> d). 24' There is a landscape area with 20 rotary sprinkler heads. After placing catchment devices for a water audit, the average precipitation rate for the entire area was calculated to be .71 "/hr. The lowest quarter (driest quarter) was calculated to be .48 "/hr. What is the distribution of uniformity (DU) for this property? a). 1.48 "/hr. b). .50 "/hr. c).. d). .5 - Answer>> c).. .48/.71 =. Use the following information for exercises 61 to 63. Drip irrigation is installed in an area that is 35' x 65'. The drip irrigation used in this area is integrated emitters (emitters that are factory installed at different intervals in the piping). These emitters are installed every 18" and the row spacing is suggested at 18" as well. The flow rate per emitter is .6 GPH (Gallon Per Hour). The manufacturer suggests installing the piping 4" from the hardscape (4" in from the borders on all sides of your area). - Answer>> extra info Approximately, how many emitters will you have installed in this area? a). 1029 b). 924 c). 1072 d). 412 - Answer>> a). 1029 (question 61 en section 3 por si ocupas ayuda) How many GPH are you flowing in this area? a). 653. b). 625 c). 717.

d). 617.4 - Answer>> d). 617. Multiply the total emitters from Exercise #61 times the GPH of each emitter to get total GPH: 1029 x .6 = 617.4 GPH How many GPM (Gallons per Minute) are you flowing in this area? a). 17. b). 10. c). 12 d). 14.2 - Answer>> b). 10. Divide the total GPH from Exercise #62 by 60 to arrive at total GPM: 617.4 / 60 = 10.3 GPM