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A test bank for applied physics, 12th edition, covering chapters 1 through 4. It includes a variety of questions and problems related to physics concepts, such as metric prefixes, scientific notation, unit conversions, problem-solving techniques, vector quantities, and motion. The questions range from fill-in-the-blanks and calculations to conceptual explanations, providing a comprehensive review of the material. It is designed to assess understanding and application of physics principles. The test bank includes problems related to kinematics, vector analysis, and unit conversions, offering a range of exercises for students to practice and reinforce their knowledge. Useful for students studying applied physics and instructors seeking assessment materials. It covers topics such as displacement, velocity, acceleration, and trigonometric ratios, providing a solid foundation in basic physics concepts.
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Applied Physics, 12th Edition by Dale Ewen Neill Schurter P Erik Gundersen
Chapter 1 - 24
Chapter 1 The Physics Tool Kit
Answer: centi
Answer: m
Write the following number(s) in scientific notation:
Answer: 4.5 × 10
Answer: 7.42 × 10
Write the following number in decimal form:
Answer: 0.
Answer: 265,000,
Fill in each blank: (Round to three significant digits when necessary.)
Answer: 1200
Answer: 6900
Answer: 0.
= ________ cm
Answer: 6.
= ________ m
Answer: 0.
Answer: 166
Answer: 2.
= ________ m
Answer: 0.
Determine the accuracy (the number of significant digits) in each measurement:
Answer: 3
Answer: 4
km
Answer: 2
Determine the precision of each measurement:
Answer: 0.1 m
Answer: 10 ft
s
Answer: 1000 s
Answer: 40.2 m
Answer: 104 m
Answer: 970 cm
Express each of the following values using scientific notation:
Answer: 1.042 × 10
mi
Answer: 6.8 × 10
in.
Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 2 Problem Solving
Answer: An exponent is a mathematical operation. A subscript is used to define a variable a
specific feature or component of a variable.
Answer: A formula is a basic equation, usually expressed in letters and numbers. A working
equation is created when the desired variable is isolated on one side of the equation.
Answer: Estimating the expected answer in problem solving can serve as a check to make sure
the answer is correct.
Answer: m = F/a
)t.
Answer: t = 2s / (v f
in the formula s = 1/2 (v f
)t.
Answer: v f
= (2s/t) - v i
Answer: h = PE / mg
h, if r = 5.0 cm and V = 250 cm
, what is h?
Answer: h = 3.2 cm
Answer: A = 61.0 cm
and a radius of 7.50 cm. What is its height?
Answer: h = 5.35 cm
hypotenuse.
Answer: 84.7 mm
Answer: 1520 cm
the adjacent side?
Answer: 12.0 cm
h. If V = 4520 m
and h = 36.0 m, find r.
Answer: r = 6.32 m
, find h.
Answer: h = 52.9 m
that each measure 8.00 m by 8.00 m for tree plantings, how much area is left for parking spaces?
Answer: A = 5810 m
Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 3 Vectors
Answer: Scalar is a quantity that specifies magnitude. Vector is a quantity that specifies both
magnitude and direction.
Answer: Distance is a scalar that specifies the magnitude or the amount that an object has
changed its position. Displacement is a vector that specifies the direct distance and direction that
an object has moved.
450 km.
Answer: 18 cm
Use graph paper to find the resultant of each set of displacements in the following problem(s).
Answer: 100 km at 27° north of east
of east.
Answer: 130 km at 38° south of east
Use a calculator to find each trigonometric ratio rounded to four significant figures in the
following problem(s).
Answer: 0.
Answer: 2.
Answer: 32.2°
Answer: 43.3 cm
length of the other leg.
Answer: 64.4 m
angle?
Answer: 55.5°
pole and to an anchor on level ground 25.0 ft from the base, what angle does the guy wire make
with level ground?
Answer: 58.0°
grain is elevated 15.0 m, how long is the conveyor?
Answer: 20.0 m
Vector x-component y-component
Answer: R x
y
Answer: v x
= - 40.8 m/s; v y
= - 19.0 m/s
Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 4 Motion
Answer: 94 km
km/h?
Answer: 2.7 h
and 30 min. If 16 h and 30 min of that time was spent sleeping and 3 h 40 min was used for meals
and refueling, what was the average speed while on the road?
Answer: 5 mi/h
Change 95.0 km/h to the speed units given in the following problem(s):
Answer: 26.4 m/s
Answer: 59.0 mi/h
Answer: 86.6 ft/s
a. Find its acceleration in ft/s
b. How far can it travel in that time?
Answer: (a) 21 ft/s2 (b) 230 ft
a. Find its acceleration in ft/s
b. How far can it travel in that time?
Answer: (a) 4.40 ft/s
(b) 385 ft
Answer: 1600 mi
strikes the wood. The arrow penetrates 3.8 cm into the wood before stopping. What is its average
acceleration (in m/s
into the wood?
Answer: - 15,000 m/s
acceleration change during the ball's flight.
Answer: There is no horizontal acceleration during the flight. The vertical acceleration (the
acceleration due to gravity) remains a constant downward 9.80 m/s
throughout the flight.
fired with a velocity of 28.3 m/s, how far from the edge of the cliff will the ball land?
Answer: 64.5 m
velocity of 28.3 m/s and at an angle of 30°, how far will the cannon ball travel?
Answer: 71.1 m
45°. What happens to the range of projectiles as the angle of launch changes from 45° to 90°?
Answer: range increases; range decreases
Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 5 Force
Answer: Inertia is the property of a body that causes it to resist a change in its motion. Inertia is
defined by the object's mass.
Answer: Mass is a measurement of inertia of a body. Weight a vector that represents the amount
of force that gravity applies to the mass.
Answer: 36.7 m/s
Answer: 19,300 N
coefficient of friction?
Answer: Starting friction is the force that attempts to prevent a stationary object from sliding.
Sliding friction is the force that resists the continuation of the object's movement. Starting friction
tends to have a higher coefficient of friction.
6 ) A wooden crate is dragged across a concrete floor. What are two things that can be done to
decrease the coefficient of friction between these two surfaces?
Answer: Lubricate the area between the two surfaces. Place rollers or ball bearings between the
two surfaces. Rolling friction can be significantly lower than sliding friction.
a concrete floor by a winch with a 450 lb capacity?
Answer: 1500 lb
8 ) A sled weighing 3350 N is pulled over snow at uniform speed by exerting a force of 1200 N.
Find the coefficient of friction.
Answer: 0.
75 N to the right; 225 N to the left; 45 N to the right.
Answer: 37 N to the left
the motion of the bicycle is - 23.5 N, what force must the cyclist apply to maintain a constant
velocity?
Answer: 23.5 N resulting in a net force of 0 N
Answer: Momentum is a measure of the amount of inertia and motion an object has or the
difficulty in bringing a moving object to rest.
Explain your answer.
Answer: The tossed tennis ball has greater momentum because it has both mass and motion.
Answer: 3.90 kg m/s
Answer: The tennis racket applies a force for a period of time. The impulse alters the ball's
velocity, thereby also changing its momentum.
tennis racket apply to the ball? What is the impulse of this interaction?
Answer: 53.8 N; 3.90 N s
145 - g projectile fired at 325 m/s.
Answer: 171 g
Answer: "Crumple zones" are used to increase the amount of time of a collision, thus reducing
the amount of force experienced by the automobile and the passengers.
stops?
Answer: A bouncing motion results in a larger change in velocity, thereby resulting in a greater
change in momentum and impulse. A ball that simply strikes a surface and stops experiences a
much smaller change in velocity and therefore smaller change in momentum and impulse.
Answer: Inelastic collisions result in two or more objects being coupled together after the
collision. Elastic collisions result in two or more objects bouncing off one another and returning to
their original shapes.
Answer: Elastic collision—two billiard balls, bowling ball and pins, tennis ball and racket.
Inelastic collision—automobiles locking together, train cars coupling together, baseball player
catching a ball in a glove.
Use the following information to answer the question(s) below:
A person is driving an automobile at 95.0 km/h and throws a bottle of mass 0.600 kg straight out
the window. (Assume there is no air resistance.)
Answer: 15.8 kg m/s
direction at 85.0 km/h?
Answer: 30.0 kg m/s
direction at 115.0 km/h?
Answer: 3 .33 kg m/s
Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 7 Concurrent and Parallel Forces
745 N (right); 372 N (left); 427 N (left); 555 N (left); 965 N (right).
Answer: 356 N (right)
a. What is the magnitude of the maximum net force the two forces can exert together?
b. What is the magnitude of the minimum net force the two forces can exert together?
Answer: (a) 643 N (b) 53 N
= 975 N, and F 2
= 745 N, and F 3
= 1175 N are applied to the same point. The
angle between F 1
and F 2
is 60.0°. The angle between F 2
and F 3
is 30.0°. F 2
is between F 1
and
. Find the resultant force.
Answer: 2260 N at 53.5° from F 1
forces is 45.0°. Find the resultant force.
Answer: 3500 N at 45.0° from F 1
without breaking?
Answer: 7
Answer: T = 3230 N; C = 2650 N
Answer: T 1
crane.
Answer: T = 3759 N; C = 5064 N
Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 8 Work and Energy
level floor by exerting a constant force of 21.0 lb.
Answer: 756 ft lb
and dump it into a 5.0 yd
dump truck?
Answer: 130,000 ft lb
the lift?
Answer: 6370 N m
1150 N is exerted on the cable, how much work is done?
Answer: 102,000 N m
Answer: 4310 ft lb/s
Answer: 6620 W or 6.62 kW
Answer: 6.95 s
Answer: 51.5 s
Answer: 204 kg
be lifted a distance of 25 m? (1 L of water has a mass of 1 kg.)
Answer: 1200 L/min
its lowest point.
Answer: 56,300 ft lb
Answer: 2500 J or 2.5 kJ
Answer: 140,000 ft lb
/min from a lake into a tank on a hill 75.0 m above the
lake. (1 m
a. What power (in kW) must be delivered by the pump?
b. What horsepower rating must this pump motor have?
c. What is the increase in potential energy of the water each minute?
d. Assuming 25% of the pump power is lost, what power (in kW) must be delivered by the pump?
Answer: (a) 3370 kW (b) 4520 hp (c) 202 MJ (d) 4210 kW
Answer: 53.8 ft/s
a. What is its velocity at its highest point of travel?
b. What maximum height does it reach?
c. At what velocity does it hit the ground?
Answer: (a) 0 (b) 797 m (c) 125 m/s
a. What is its velocity as it hits the water?
b. How long does it take to hit the water?
c. What is its kinetic energy as it hits the water?
Answer: (a) 56.7 ft/s (b) 1.76 s (c) 99.8 ft lb
a. What is its velocity after falling 25.0 m?
b. What is its velocity as it hits the water 125 m below?
c. What is its kinetic energy as it hits the water?
Answer: (a) 24.3 m/s (b) 50.5 m/s (c) 325 J
the ground. What is the total work done?
Answer: W = 420 ft lb
a. How much work was done?
b. How much power (in horsepower) did it take?
Answer: (a) 7,000 ft lb (b) P = 1.1 hp
motor's power? Express your answer in both watts and horsepower.
Answer: P = 96 W; P = 1.29 hp
Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 9 Rotational Motion
gear revolves at 80.0 rpm. How many teeth does the second gear have?
Answer: 30 teeth
rpm of the second gear.
Answer: 57.5 rpm
Answer: Yes
second pulley with diameter 10.0 cm. Find the rpm of the second pulley.
Answer: 15 rpm
driven at 25 rpm by the first.
Answer: 2.00 cm
driven gear in a gear train?
Answer: An idler allows both gears to rotate in the same direction.
opposite direction?
Answer: Opposite
Answer: Since the gears are connected, they both rotate together.
Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 10 Simple Machines
Answer: Simple machines result in useful work. Simple machines are typically used to reduce the
amount of effort force that is needed to do work.
Provide three examples of complex machines.
Answer: Pencil sharpener, bicycle, snow blower, can opener, automobile
Answer: The ratio of work output of a machine to the work input of a machine.
Answer: No. The work input to a machine is partially used to overcome internal friction within
the machine.
the end of the pole is positioned in a fixed fulcrum? Will the fishing pole have a mechanical
advantage greater or less than 1.00?
Answer: Third Class Lever; MA < 1.
sports cars.
Answer: An increased radius provides the wheel and axle with a greater mechanical advantage.
Such an advantage is needed for a massive truck.
jack handle lifts the car that weighs 96 lb.
Answer: 32 : 1
weighs 960 lb. What could be done to the jack to increase its mechanical advantage?
Answer: Increase the length of the handle or increase the effort force.
is 8.00 ft; the distance from the weight to the fulcrum is 2.00 ft. Find the weight lifted. Find the
mechanical advantage of the lever.
Answer: 34 lb; 4.00:
axle; the center of the load is 1.50 ft from the axle. How much upward force does the worker exert
to lift the handles of the wheelbarrow?
Answer: 84.4 lb