

Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Community
Ask the community for help and clear up your study doubts
Discover the best universities in your country according to Docsity users
Free resources
Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors
The formula and explanation for calculating the surface area of a sphere using integration. It includes special cases and answers to common questions such as rotating around the y-axis and using shells.
What you will learn
Typology: Schemes and Mind Maps
1 / 3
This page cannot be seen from the preview
Don't miss anything!
In this example we will complete the calculation of the area of a surface of rotation. If we’re going to go to the effort to complete the integral, the answer should be a nice one; one we can remember. It turns out that calculating the surface area of a sphere gives us just such an answer. Remember that in an earlier example we computed the length of an infinites- imal segment of a circular arc of radius 1:
ds =
1 − x^2
dx
x 1 x 2
Figure 1: Part of the surface of a sphere.
For this example we’ll let the radius equal a, so that we can see how the surface area depends on the radius. Then:
y =
a^2 − x^2 y′^ = −x √ a^2 − x^2
ds =
x^2 a^2 − x^2
dx
a^2 − x^2 + x^2 a^2 − x^2
dx
a^2 a^2 − x^2
dx
The formula for the surface area indicated in Figure 1 is:
Area =
∫ (^) x 2
x 1
2 πy ds
∫ (^) x 2
x 1
2 π
y ︷√ ︸︸ ︷ a^2 − x^2
ds ︷√ ︸︸ ︷ a^2 a^2 − x^2 dx
∫ (^) x 2
x 1
2 π
a^2 − x^2
a √ a^2 − x^2
dx
∫ (^) x 2
x 1
2 πa dx
= 2 πa(x 2 − x 1 )
Special Cases
When possible, we should test our results by plugging in values to see if our answer is reasonable. Here, if we set x 1 = 0 and x 2 = a we should get the surface area of a hemisphere of radius a:
0 a
Figure 2: Right hemisphere.
2 πa(x 2 − x 1 ) = 2 πa(a − 0) = 2 πa^2
We get the surface area of the whole sphere by letting x 1 = −a and x 2 = a:
2 πa(x 2 − x 1 ) = 2 πa(a − (−a)) = 4 πa^2
Question: Would it be possible to rotate around the y-axis? Answer: Yes. If we rotate around the y axis and integrate with respect to x (calculating the surface area of a vertical slice, as we did here) we’d be adding up little strips of area. If we integrate with respect to y and find the surface area between two vertical positions y 1 and y 2 we’d get exactly the same calculation.
Question: Can you compute surface area using shells? Answer: The short answer is “not quite”. We use the word shell to describe something which has a thickness dx. Shells have volume, integrals which involve shells compute volumes, not surface areas.