Structure and Function of Biomolecules - Solved Midterm 1 - Summer 2012 | BIS 102, Exams of Biology

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Copyright © UC Regents Davis campus, 2005- 12. All Rights Reserved. May not be re-distributed without prior written consent of course instructor. : 1 of 2 BIS 102 Name Ken Summer, 2012 Last ~ First K. Hilt First Midterm Score (100): Kp=x/(y-x) Ky =x'Ay-x) pH = pK, + log {[6)fa]} (Ky) (Ky) = 1x 10" AG = AH - TAS pH=(pKg,+pKg,V/2 0 F=(q'q?)/er pK,’s of amine acid side chains: _D (3.9), E (4.2), H (6.0), C (8.3), ¥ (10.1), K (10.5), R (12.5) pK, of amino acid «-COOH (2.1); pK, of amino acid a-NH,’ (9.6) pK, of oligopeptide N-terminus (7.4); pK, of oligopeptide C-terminus (3.6) Equations: 1. The oligopeptide V-Q-N-R-E-H-W-C-K was isolated from a plant. (27 pts.) a) Draw its complete structure in the form that would predominate at pH 7. Hoo Hos Hoo 4 @ ' ¢@ H 2 o ng 8 _ + Loy 4 i i) y ‘ 1 oo a a HN — Om Emi gG SONG CONT en-AN- ex due - cow ene~ “eg <- Neem CoD ven, tH, ot He (cH) 4 cH, A che 4 eH, HoH, Pa H2), os oh roe uae ite vs = Payot +NHy = NH Ls, go> cro 2 ce NU, ye . NH Hy (20 pts.) b) Calculate its net charge, to the 0.01, at pH 8. Show all/calculations.|Put yor final answer here: -©.14:__. You mayluse the bagk of this . -l +1 pi ey Soe 7M Noy He we ley a6>) = Fat! k ony Bo = BS + boy ce BAF 2 we 0.3 = logy % . . ose = Soe & a= ~— = 0.20 noe on bhe 2.591 = 6.334 Ol on a4HY-Py = 0. 3a (0-20)(41) =*0.20 (15 pts.) c) The oligopeptide was subjected to hydrolysis using 6 M HCI ovemight at 110°C. The resulting hydrolysate was then subjected to ion exchange chromatography, as we discussed in class. Using the axes drawn below, indicate the elution profile that you would expect. Label each peak. Label the x- and y-axes. Indicate carefully where each buffer begins. Label each elution buffer. The peak sizes and locations should be drawn accurately. pt 3 are el > in any orher j t | A (z B K NAT (VY wc) aH Test tehe # or Time