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TRUSS BY FLEXIBILITY METHOD.Determine forces in members and support reactions.
Typology: Study notes
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p
p
2p √2p
p
3p p
Now we find the forces in members by application of unit horizontal
force at C.
Member Length Member
forces due
to external
forces
S
Member
forces due
to unit
load at C
S 1
Member
forces due
to unit
force
along DB
S 2
1
2
AB L/A.E 0 O -1/√2 0 0
BC L/A.E P -1 -1/√2 -PL/A.E -PL/√2AE
CD L/A.E P 0 -1/√2 0 -PL/√2AE
AD L/A.E -2P 0 -1/√2 0 √2PL/AE
AC L/A.E -√2P √ 2 1 -2√2PL/AE^ -2PL/AE
BD √2L/A.E 0 0 1 0 0
Q−
QL=
QL
QL
QL
1
= Reaction at C.
2
= Force in member DB.
QL
= Deflection at C due to applied load at C.
QL
= Deflection in member DB due to applied load in
member BD
QL
Q
QL
L/AE -^ L/AE
1
2
1.17p
0.55p
1.82p 0.77p
0.17p
0.71p
1.27p 0.72p
0.24p
0.24p
1.72p