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An overview of strong acids and bases, explaining their characteristics, ionization processes, and the calculation of their ph values. Strong acids and bases are strong electrolytes that completely ionize in water, resulting in a significant number of hydrogen or hydroxide ions in solution. Examples of common strong acids and bases, such as hydrochloric acid and sodium hydroxide, and illustrates how to calculate their ph values using the given concentrations.
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Strong Acids and Bases
Acidic character of an acid is associated with the proton (H+) in solution. Higher number of proton means stronger the acid. Similarly, the basic character is due to the presence of hydroxide ions (OH - ) in solution. Higher the number of hydroxide ions in solution means the stronger the base.
Strong acids and bases are strong electrolytes that are assumed to ionize completely in water. That means, when they are completely ionized, no non-ionized form is present is solution. The ionization of strong acids and bases are shown by using single arrows (Æ) in chemical equations:
Strong acids
Hydrochloric acid: HCl(aq) + H 2 O(l) Æ H 3 O+^ (aq) + Cl-(aq) Hydrobromic acid: HBr(aq) + H 2 O(l) Æ H 3 O+^ (aq) + Br - Hydroiodic acid: HI(aq) + H 2 O(l) Æ H 3 O+^ (aq) + I - Nitric acid: HNO 3 (aq) + H 2 O(l) Æ H 3 O+^ (aq) + NO 3 - (aq) Perchloric acid: HClO 4 (aq) + H 2 O(l) Æ H 3 O+^ (aq) + ClO 4 -^ (aq) Sulfuric acid: H 2 SO 4 (aq) + H 2 O(l) Æ H 3 O+^ (aq) + HSO 4 -
Note that the sulfuric acid is the diprotic acid and ionizes in two stages. Here only the first stage of ionization is shown.
Strong Bases
Sodium hydroxide: NaOH(aq) Æ Na +(aq) + OH-^ (aq) Potassium hydroxide: KOH(aq) Æ K+(aq) + OH -^ (aq) Barium hydroxide: Ba(OH) 2 (aq) Æ Ba 2+(aq) + 2OH-^ (aq)
pH of Strong Acids and Bases
Calculating the pH of strong acids and bases is not very difficult if you remember that they completely ionize in solution. Let us illustrate this with the following example.
Example
Calculate the pH of (a) 2.5 x 10-4^ M HCl solution and (b) 0.25M Ba(OH) 2 solution.
Answer
(a) HCl is strong acid and ionizes completely at equilibrium , which is given by
HCl(aq) Æ H+^ (aq) + Cl-(aq)
According to this equation, one mole of HCl yields one mole of H+^ and one mole of Cl -^ And also, when ionization is complete, no HCl is left in solution, only H+ and Cl -^ ions exist. Therefore,
[H+^ ] = [Cl - ] = 2.5 x 10 -4^ M
Then pH = - log (2.5 x 10-4^ ) = 3.
(b) First of all, bases do not give the pH directly like acids because they do not produce H+^ ions. They rather give OH-^ concentrations, which are converted to pH. Ba(OH) 2 is a strong base and ionizes according to the following equation.
Ba(OH) 2 (aq) Æ Ba 2+(aq) + 2OH-^ (aq)
Each mole of Ba(OH) 2 produces one mole Ba 2+^ and two moles of OH -^ ions, and no Ba(OH) 2 is left unionized in solution. Whatever the concentration of Ba(OH) (^2) we started with, it is completely transformed into Ba 2+^ ion and OH -^ ion. Then
[OH - ] = 2 x0.25 M = 0.50 M pOH = -log(0.5) = 0. pH = 14.0 – pOH = 14.0 – 0.30 = 13.
Ionization Constants of Strong Acids and Bases
Since strong acids and bases ionize completely, their ionization constants are very large and are not determinable by the experiments. Due to this, they are not available in the literature. Consider the following example to see how the ionization constants of strong acids are very large.
HA (aq) Æ H+^ (aq) + A-^ (aq)
Here HA indicates the acid in a general form. At equilibrium, [H+^ ] >0 and [A -^ ] >0 and [HA]=0. Thus the ionization constant becomes
a
The mathematical interpretation of this equation is that anything upon zero is infinity, i.e., a very large number. Hence, ionization constants for acids are very large.
Same explanation can also be provided for ionization constants of strong bases.