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Typology: Exercises
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Everett Community College Student Support Services Program
Write a balanced equation for the reaction of sulfuric acid with gallium hydroxide to form water and gallium sulfate:
From the equation in part 1, determine the mass of gallium sulfate that can be made with 145 grams of sulfuric acid and 320 grams of gallium hydroxide.
Which is the limiting reagent in part 2?
How much of the excess reagent will remain once the reaction is complete?
3 H 2 SO 4 + 2 Ga(OH) 3 Ga 2 (SO 4 ) 3 + 6 H 2 O
First determine how much gallium hydroxide you would need with 145 g of sulfuric acid. If the amount of gallium hydroxide is less than 320 g then the sulfuric acid is the limiting reagent. If it exceeds 320 g then the gallium hydroxide is the limiting reagent.
145 g H 2 SO 4 x 1 mol H 2 SO 4 x 2 mol Ga(OH) 3 x 120.74 g Ga(OH) 3 = 98.08 g H 2 SO 4 3 mol H 2 SO 4 1 mol Ga(OH) 3
= 119 g Ga(OH) 3 (which means the limiting reagent is H 2 SO 4 )
145 g H 2 SO 4 x 1 mol H 2 SO 4 x 1 mol Ga 2 (SO 4 ) 3 x 427.638 g Ga 2 (SO 4 ) 3 = 98.08 g H 2 SO 4 3 mol H 2 SO 4 1 mol Ga 2 (SO 4 ) 3
= 211 g Ga 2 (SO 4 ) 3
Sulfuric acid
320 g Ga(OH) 3 - 119 g Ga(OH) 3 = 200 g Ga(OH) 3