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Stoichiometry Study Guide: Calculating Molar Mass and Balancing Equations, Exercises of Stoichiometry

A study guide for understanding stoichiometry, focusing on calculating molar mass and balancing chemical equations. It includes examples of calculating molar mass for elements and compounds, as well as balancing equations using grams and moles. The guide also covers mole-mole and mass-mass stoichiometry.

Typology: Exercises

2021/2022

Uploaded on 09/12/2022

mcboon
mcboon 🇺🇸

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Name_____________________________________________Period_________________________
Stoichiometry The Mole Study Guide
Grams and Moles Review (3 points each)
Calculate the Molar Mass of each element or compound
1) Sn Tin! 118.71 g/mole
2) Fe2O3 159.69 g/mole
3) H2SO4 98.1 g/mole
Calculate the mass in grams
4) 8 moles of NH3 8 x 17.031 = 136.35 g
5) 10 moles of AgNO3 10 mol x 169.874 g/mol = 1698.7 g
Calculate the amount in moles
6) 80.1 grams of Ca 80.1 g Ca ÷ 40.078 g/mol = 1.998 = 2.00 moles
7) 48.4 grams of Cu(NO3)2.3H2O 48.4 g ÷ 241.6 g/mol = 0.200 moles
Find molar mass! 1 x Cu, 2 x N, 6 x H, 6 + 3 = 9 O. MM = 241.6 g/mol
Mole-Mole Stoichiometry
Given the reaction 4 Fe + 3 O2 2 Fe2O3
8) Given 64 moles of Fe and excess O2, how many moles of Fe2O3 can be made?
64 mol Fe x 2 mol Fe2O3 = 128/4 = 32 mol Fe2O3
4 mol Fe
9) Given 48 moles of O2 and excess Fe, how many moles of Fe2O3 can be made?
48 mol O2 x 2 mol Fe2O3 = 32 mol Fe2O3
3 mol O2
10) To make 4 moles of Fe2O3, how many moles of Fe are necessary? How many moles of O2?
4 mol Fe2O3 x 4 mol Fe = 8 mol Fe
2 mol Fe2O3
4 mol Fe2O3 x 3 mol O2 = 6 mol O2
2 mol Fe2O3
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Name_____________________________________________Period_________________________

Stoichiometry – The Mole Study Guide

Grams and Moles Review (3 points each) Calculate the Molar Mass of each element or compound

  1. Sn Tin! 118.71 g/mole
  2. Fe 2 O 3 159.69 g/mole
  3. H 2 SO 4 98.1 g/mole Calculate the mass in grams 4 ) 8 moles of NH 3 8 x 17.031 = 136.35 g
  4. 10 moles of AgNO 3 10 mol x 169.874 g/mol = 1698.7 g Calculate the amount in moles 6 ) 80.1 grams of Ca 80.1 g Ca ÷ 40.078 g/mol = 1.998 = 2.00 moles 7 ) 48.4 grams of Cu(NO 3 ) 2 .3H 2 O 48.4 g ÷ 241.6 g/mol = 0.200 moles Find molar mass! 1 x Cu, 2 x N, 6 x H, 6 + 3 = 9 O. MM = 241.6 g/mol Mole-Mole Stoichiometry Given the reaction 4 Fe + 3 O 2  2 Fe 2 O 3
  5. Given 64 moles of Fe and excess O 2 , how many moles of Fe 2 O 3 can be made? 64 mol Fe x 2 mol Fe 2 O 3 = 128/4 = 32 mol Fe 2 O 3 4 mol Fe
  6. Given 48 moles of O2 and excess Fe, how many moles of Fe 2 O 3 can be made? 48 mol O2 x 2 mol Fe2O3 = 32 mol Fe2O 3 mol O
  7. To make 4 moles of Fe 2 O 3 , how many moles of Fe are necessary? How many moles of O 2? 4 mol Fe2O3 x 4 mol Fe = 8 mol Fe 2 mol Fe2O 4 mol Fe2O3 x 3 mol O2 = 6 mol O 2 mol Fe2O

Mass-Mass Stoichiometry 11 ) Balance the following equation:

_ 1 _AlCl 3 + _ 3 _CH 3 OH  _ 1 _Al(OCH 3 ) 3 + _ 3 _HCl

You are given 13.3 grams of AlCl 3. How many grams of Al(OCH 3 ) 3 can be produced in this reaction? Fill in the blanks in the calculation below:

13.3_g AlCl 3 x 1 mol AlCl 3 x __ 1 mol Al(OCH 3 ) 3 x ___120.1 g Al(OCH 3 ) 3

133.3 g AlCl 3 1 mol AlCl 3 1 mol Al(OCH 3 ) 3

= 1597.33 = 12.0 g Al(OCH 3 ) 3