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stoichiometry cheat sheet, Cheat Sheet of Chemistry

Great stoichiometry cheat sheet with examples

Typology: Cheat Sheet

2018/2019
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Uploaded on 09/02/2019

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STOICHIOMETRY CHEAT SHEET Grams of Known
Na = 22.99 g
O = 15.99 g
H = 1.00 g
Grams (mass) to Moles Example 39.98 g
grams of known* 1 mol of known 435 g NaOH 1 mol NaOH
1 grams of known 1 39.98 g NaOH
Balanced Equation (Mole to Mole Ratio)
2NaOH + BaCl2 2NaCl + Ba(OH)2
Moles to Moles Example
mol of known ? mol of unknown 10.9 mol NaOH 1 mol BaCl2
1 ? mol of known 1 2 mol NaOH
Grams of Unknown
Ba = 137.3 g
Moles to Grams (mass) 2-Cl = 70.9 g
208.2 g
mol of unknown grams of unknown Example
1 1 mol unknown 5.45 mol BaCl2 208.2 g BaCl2
1 1 mol BaCl2
= 1133 g BaCl2
Grams to Moles to Moles to Grams (Putting it all together)
grams of known* 1 mol of known ? mol of unknown grams of unknown
1 grams of known ? mol of known 1 mol unknown
Example
435 g NaOH 1 mol NaOH 1 mol BaCl2 208.2 g BaCl2
1 39.98 g NaOH 2 mol NaOH 1 mol BaCl2
*given in problem *what you are solving for in problem
= mol of known
= 10.9 mol NaOH
= mol of unknown
= 5.45 mol BaCl2
= grams of unknown*
= grams of unknown*
= 1133 g BaCl2
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STOICHIOMETRY CHEAT SHEET Grams of Known

Na = 22.99 g O = 15.99 g H = 1.00 g

Grams (mass) to Moles Example 39.98 g

grams of known* 1 mol of known 435 g NaOH 1 mol NaOH 1 grams of known 1 39.9 8 g NaOH Balanced Equation (Mole to Mole Ratio) 2NaOH + BaCl 2 2NaCl + Ba(OH) 2

Moles to Moles Example

mol of known? mol of unknown 10.9 mol NaOH 1 mol BaCl 2 1? mol of known 1 2 mol NaOH Grams of Unknown Ba = 137.3 g

Moles to Grams (mass) 2-Cl = 70.9 g

208.2 g

mol of unknown grams of unknown Example

1 1 mol unknown 5.45 mol BaCl 2 208.2 g BaCl 2 1 1 mol BaCl 2 = 1133 g BaCl 2

Grams to Moles to Moles to Grams (Putting it all together)

grams of known* 1 mol of known? mol of unknown grams of unknown 1 grams of known? mol of known 1 mol unknown

Example

435 g NaOH 1 mol NaOH 1 mol BaCl 2 208.2 g BaCl 2 1 39.9 8 g NaOH 2 mol NaOH 1 mol BaCl 2 given in problem what you are solving for in problem = mol of known = 10.9 mol NaOH = mol of unknown = 5.45 mol BaCl 2 = grams of unknown = grams of unknown = 1133 g BaCl 2