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Calculating Standard Deviation of Density Data, Lecture notes of Mathematical Statistics

How to calculate the standard deviation of a set of density data using the given formula. The document also discusses the significance of standard deviation in measuring the spread of data and its relationship to precision. A table of mass, volume, and density data for six different pieces of copper, as well as the calculation of the mean density and standard deviation.

What you will learn

  • What is the formula for calculating standard deviation?
  • How does standard deviation measure the spread of data?
  • What is the relationship between standard deviation and precision?

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2021/2022

Uploaded on 09/27/2022

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Standard Deviation
The following mass and volume data was collected by using the water
displacement method for six different pieces of copper. The density was
calculated for each trial and is shown below.
Mass Volume Density
(g) (cm3) (g/cm3)
08.60 1.00 8.60
15.20 1.70 8.94
18.60 2.00 9.30
22.10 2.60 8.50
31.90 3.80 8.39
42.20 4.70 8.98
When analyzing a set of data, it is common to show the distribution of that data.
Three factors showing distribution are shape, center point, and spread of the
data. The shape of the data in graphical format refers to the data being
symmetrical or asymmetrical, the center point is usually given by the average
(mean) and the spread is given by the minimum and maximum data values.
A common way to express the center point is using the arithmetical average
(mean) and is given by:
xave = (x1 + x2 + … + xn)/n also written as xave = 1/nΣxi
The mean is calculated by summing the data values and dividing by the number
of data values.
Standard deviation is used to measure the spread by showing how far the data
values are from the mean and is given by:
s = (1/(n-1)Σ(xi – xave)2)½
Standard deviation measures the spread about the mean in the original units of
measure. As the data becomes further from the mean, s, gets larger. Another
thing to keep in mind is that the standard deviation is strongly influenced by
outliers.
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Standard Deviation

The following mass and volume data was collected by using the water displacement method for six different pieces of copper. The density was calculated for each trial and is shown below.

Mass Volume Density (g) (cm^3 ) (g/cm^3 )

When analyzing a set of data, it is common to show the distribution of that data. Three factors showing distribution are shape, center point, and spread of the data. The shape of the data in graphical format refers to the data being symmetrical or asymmetrical, the center point is usually given by the average (mean) and the spread is given by the minimum and maximum data values.

A common way to express the center point is using the arithmetical average (mean) and is given by:

xave = (x 1 + x 2 + … + xn)/n also written as xave = 1/nΣxi

The mean is calculated by summing the data values and dividing by the number of data values.

Standard deviation is used to measure the spread by showing how far the data values are from the mean and is given by:

s = (1/(n-1)Σ(xi – xave)^2 )½

Standard deviation measures the spread about the mean in the original units of measure. As the data becomes further from the mean, s, gets larger. Another thing to keep in mind is that the standard deviation is strongly influenced by outliers.

To calculate the standard deviation, s, of the densities:

ƒ Calculate the mean density, Dave.

Dave = (D 1 + D 2 + D 3 + D 4 + D 5 + D 6 )/

Dave = (8.60 + 8.94 + 9.30 + 8.50 + 8.39 + 8.98) g/cm^3 /6 = 8.78 g/cm^3

ƒ Subtract the mean from each density value as shown in the table below.

ƒ Square each of the differences.

ƒ Divide the sum of the squares by the number of density values, minus one (n-1).

ƒ Take the square root of the result in the previous step.

D - Dave (D – Dave)^2 (g/cm^3 ) (g/cm^3 ) 2

The formula for standard deviation is given by:

s = (1/(n-1)Σ(xi – xave)^2 )½

and substituting the table values yield:

s = (0.0322+0.0262+0.272+0.0782+0.152+0.0402+/5)½^ = 0.345 g/cm^3

The smaller the standard deviation, s, the closer the density values are to the average density while a large standard deviation means the density values lie further from the mean.

For purposes of illustration, we will assume normal distributions. Normal distributions are marked by curves that are symmetrical, single-peaked, and bell-shaped.

The standard deviation for the density data is 0.345 g/cm^3. Standard deviation always has the same units as the original data. A standard deviation of 0.345 g/cm^3 means that 68% of subsequent density measurements will lie within ± 0.346 g/cm^3 of the average value (± 1 standard deviation). The values will lie in the range:

8.43 g/cm^3 ≤ 8.78 g/cm^3 ≤ 9.13 g/cm^3

It also means that 95% of further density values will lie within ± 2(0.346 g/cm^3 ) or 0.652 g/cm^3 of the average value (± 2 standard deviations). The values will lie in the range:

8.09 g/cm^3 ≤ 8.78 g/cm^3 ≤ 9.47 g/cm^3