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Sm A Mathematics Boot Camp for Science and Engineering Students, 1st Edit
Typology: Exams
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Aircraft Performance: An Engineering Approach, Mohammad Sadraey, 2
nd ed., CRC, 2023
Chapter 1-
The software package Mathcad is used to solve problems.
3
Sea level:
5000 m: (Equ 1.6)
(Equ 1.16)
(Equ 1.23)
h 5000 m ISA L1^ 6.^
1000 m
kg K
o
101325 Pa
o
o
L1 h 255.5K
o
o
54000.3Pa
kg
m
3
Sea level:
5000 m: (Equ 1.6)
(Equ 1.16)
Sea level:
20000 ft: (Equ 1.6)
(Equ 1.16)
(Equ 1.23)
h 5000 m ISA 10 L1 6.
1000 m
kg K
o
101325 Pa
o
o
L1 h 245.5K
o
o
52714.2Pa
h 20000 ft ISA 15 L1 2
1000 ft
kg K
o
101325 Pa
o
o
o
L1 h 263K T 20
o
o
48143.9Pa P 20
lbf
ft
2
kg
m
3
slug
ft
3
Sea level:
Second layer:
(Equ 1.16)
(Equ 1.23)
(Equ 1.25)
Sea level:
Second layer:
h 80000 ft ISA 20 R1 287
kg K
o
101325 Pa o
slug
ft
3
o
o
o
o
o
20098.1Pa P 80
lbf
ft
2
kg
m
3
slug
ft
3
o
h 70000 ft ISA
o
o
4
4
3
(Equ 1.23)
4 Pa R1 287
kg K
kg
m
3
given h 6500
7000 h
find (h ) 6215.
Sea level:
(Equ 1.6)
(Equ 1.35)
Sea level:
Table 1.
(Equ 1.29)
(Equ 1.30)(Equ 1.23)
h 20000 ft ISA L1^2
1000 ft
km
hr
m
s
kg K
o
o
o
L1 h 248.15K T 20
a R1T 20
m
s
a
kg K
o
101325 Pa
o
g
1.7051 kPa
v
g
v
g
3 Pa
a
o
v
4 Pa
a
o
kg
m
3
Sea level:
(Equ 1.34)
(Equ 1.34)
(Equ 1.34)
kg K
o
o
a R1T o
m
s
b
o
a R1T b
m
s
c
o
a R1 T c
m
s
o
(Equ 1.21)
(Equ 1.36)
Sea level:
(Equ 1.6)
App B: Interpolation:
(Equ 1.23)
o
101325 Pa h 60000 ft M1 2.
60
o 0.2234 e
36089 ft h
20807 ft
7173.267 Pa
q 0.7 P 60
2
24303Pa q 24.303kPa
h 29035 ft R1 287
kg K
1000 ft
o
o
o
L1 h 230.08K T1 43.07 °C
h 29035 ft
30000 h Find P1( ) 657.
lbf
ft
2
4 Pa
kg
m
3
slug
ft
3
Second layer:
(Equ 1.35)
h 12000 m ISA V1 2443
km
hr
m
s
kg K
a R1T 12
m
s
a
(Equ 1.6)
(Equ 1.34)
(Equ 1.35)
(Equ 1.6)
(Equ 1.34)
(Equ 1.35)
Sea level:
(Equ 1.6)
(Equ 1.26)
b
o
b
L1 h 268.15K T 20
a R1T 20
m
s
a
V1 M1 a 590.
m
s
mile
hr
c
o
c
L1 h 228.15K T 20
a R1T 20
m
s
a
V1 M1 a 545
m
s
mile
hr
h 10000 m ISA L1 6.
1000 m
o
o
o
L1 h 223.15K T 10
a 1.485 10
6
kg
m s K
1
2
b 110.4 K
a T 10
b
5
kg
m s
Total Distance traveled; Circumference:
(Equ 1.35)
a 340
m
s
6400 km
t 24 hr t^ 8.64^10
4 s
40212.4 km
t
m
s
a
lbf
ft
2
18821.7Pa P 40
0.186atm
3
T T T Lh T C K
o
ISA o
15 0. 002 2000 30 41 314. 15 2000
P Pa
T
T
T
T
P
P
o o
ISA
o
ISA
101325 0. 9356 94800
15 273. 15 30
15
256
256
2000
o
7. 8 0. 8 6. 24 v g
g
v P P
P
P
P P P kPa a v
94. 8 6. 24 88. 56
kg dry air
kgHO
P
P
a
v (^) 2
0438
56
24
0. 622 0. 622
kg
RT
PV
m m
a
v a
88
287 314. 15
56 160
0438
o
Sea level:
(Equ 1.6)
h 25000 ft L1^2
1000 ft
o
o
o
L1 h 238.15K T 12
LE
o
o
o
Sea level:
(Equ 1.23)
(Equ 1.23)
Sea level:
Summer:
Table 1.
(Equ 1.29) Winter:Table 1.2 (Equ 1.30)(Equ 1.23)(Equ 1.29)(Equ 1.30)(Equ 1.23)
kg K
o
110325 Pa
o
kg
m
3
slug
ft
3
o
kg
m
3
slug
ft
3
kg K
o
101325 Pa
o
o
g
5.628 kPa
v
g
v
g
3 P Pa a
o
v
4 Pa
s
a
o
kg
m
3
o
o
g
0.4 kPa
v
g
v
g
P 40Pa a
o
v
5 Pa
w
a
o
kg
m
3
s
w
(Equ 1.20)
(Equ 1.36)
o 101325 Pa h 14500 m M1 0.
o 0.2234 e
11000 m h
6342 m
13035.357 Pa
q 0.7 P1 M
2 3284.9 Pa q 3.285kPa
Sea level:
(Equ 1.6)
(Equ 1.26)
50000 ft: (Equ 1.7)
(Equ 1.21)
(Equ 1.23)