Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Section 2.3 – Linear and Angular Velocities, Lecture notes of Physics

b) Find the distance traveled by P along the circle in 6 seconds. c) Find the linear speed of P in cm per sec. Solution a) t.

Typology: Lecture notes

2021/2022

Uploaded on 09/12/2022

arjaa
arjaa 🇺🇸

4.2

(5)

229 documents

1 / 18

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
21
Section 2.3 Linear and Angular Velocities
The most intuitive measure of the rate at which the rider is traveling around the wheel is what we call
linear velocity.
Another way to specify how fast the rider is traveling around the wheel is with what we call angular
velocity.
Linear Speed
Definition
If P is a point on a circle of radius r, and P moves a distance s on
the circumference of the circle in an amount of time t, then the
linear velocity, v, of P is given by the formula
distance
speed time
s
vt
Example
A point on a circle travels 5 cm in 2 sec. Find the linear velocity of the point.
Solution
Given: s = 5cm
t = 2 sec
5
2 cm
sec
s
vt

/2.5 cm sec
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff
pf12

Partial preview of the text

Download Section 2.3 – Linear and Angular Velocities and more Lecture notes Physics in PDF only on Docsity!

Section 2.3 – Linear and Angular Velocities

The most intuitive measure of the rate at which the rider is traveling around the wheel is what we call linear velocity.

Another way to specify how fast the rider is traveling around the wheel is with what we call angular velocity.

Linear Speed

Definition

If P is a point on a circle of radius r , and P moves a distance s on

the circumference of the circle in an amount of time t , then the

linear velocity , v , of P is given by the formula

speed distance time

v s

t

Example

A point on a circle travels 5 cm in 2 sec. Find the linear velocity of the point.

Solution

Given: s = 5 cm

t = 2 sec

5 2

cm sec v s  (^) t  2.5 cm / sec

Angular Speed

Definition

If P is a point moving with uniform circular motion on a circle of

radius r , and the line from the center of the circle through P sweeps

out a central angle  in an amount of time t , then the angular velocity ,

 (omega), of P is given by the formula

 ^  t where  is measured in radians

Example

A point on a circle rotates through^3 4 radians in 3 sec. Give the angular velocity of the point.

Solution

Given:  = 34  rad

t = 3 sec

3 4 3

rad sec

^  4 rad / sec

Example

A bicycle wheel with a radius of 13.0 in. turns with an angular velocity of 3 radians per seconds. Find the distance traveled by a point on the bicycle tire in 1 minute.

Solution

Given: r = 13.0 in.

 = 3rad/ sec

t = 1 min = 60 sec.

t  ^ 

 t  s  r    sr

t s   r

s   tr

2,340 inches 2, or (^) 12  195 ft

Example

Suppose that P is on a circle with radius 10 cm, and ray O P is rotating with angular speed s

 rad / ec.

a) Find the angle generated by P in 6 seconds

b) Find the distance traveled by P along the circle in 6 seconds.

c) Find the linear speed of P in cm per sec.

Solution

a)   t

18 .6^3 rad

^ ^ 

b) sr

s  10   3 ^103  cm

c) vst

10 3 6 v

^ 

(^5) / c 9 ^  cm se

Example

A belt runs a pulley of radius 6 cm at 8 0 rev / min. a) Find the angular speed of the pulley in radians per sec. b) Find the linear speed of the belt in cm per sec.

Solution

a)  80 min rev^  1min 6 0sec 12 rev^ 

(^8) / c 3

^  rad se

b) vr

^ 

 50 cm / s ce

Example

The diameter of the Ferris wheel is 250 ft , the distance from the ground to the bottom of the wheel is 14 ft , and one complete revolution takes 20 minutes, find

a. The linear velocity, in miles per hour, of a person riding on the wheel.

b. The height of the rider in terms of the time t , where t is measured in minutes.

Solution

Given :  = 1 rev = 2 rad

t = 20 min.

250 2 2 125 rD   ft

t a.  ^  r or v t ^ 

2 20

^ 

 10  rad / min

v  r 

 (125 ft ) 10  rad / min 39.27 ft / min

min

60min 1 39.27 (^1) 5, ft (^) mile vhr ft

0.45 mi / hr

1

b. cos  OPOP

125

^ OP

OP 125cos  HPP 0  14

 OP 0  OP  14

 125  125cos  14  139 125cos 

t  ^    t

10 t

^ 

H 139 125cos  10 t   ^ 

H

P 0

P 1

14 ft

O

P

7. A Ferris wheel has a radius 50.0 ft. A person takes a seat and then the wheel turns 23  rad.

a) How far is the person above the ground?

b) If it takes 30 sec for the wheel to turn 23  rad , what is the angular speed of the wheel?

8. A fire truck parked on the shoulder of a freeway next to a long block wall. The red light on the top of the truck is 10 feet from the wall and rotates through a complete revolution every 2 seconds. Find the equations that give the lengths d and in terms of time.

9. Suppose that point P is on a circle with radius 60 cm, and ray OP is rotating with angular speed 12 

radian per sec.

a) Find the angle generated by P in 8 sec.

b) Find the distance traveled by P along the circle in 8 sec.

c) Find the linear speed of P in 8 sec.

10. Tires of a bicycle have radius 13 in. and are turning at the rate of 215 revolutions per min. How fast is the bicycle traveling in miles per hour? ( Hint : 1 mi = 5280 ft.)

11. Earth travels about the sun in an orbit that is almost circular. Assume that the orbit is a circle with radius 93,000,000 mi. Its angular and linear speeds are used in designing solar-power facilities. a) Assume that a year is 365 days, and find the angle formed by Earth’s movement in one day. b) Give the angular speed in radians per hour. c) Find the linear speed of Earth in miles per hour. 12. Earth revolves on its axis once every 24 hr. Assuming that earth’s radius is 6400 km, find the following. a) Angular speed of Earth in radians per day and radians per hour. b) Linear speed at the North Pole or South Pole c) Linear speed ar a city on the equator 13. The pulley has a radius of 12.96 cm. Suppose it takes 18 sec for 56 cm of belt to go around the pulley. a) Find the linear speed of the belt in cm per sec. b) Find the angular speed of the pulley in rad per sec. 14. The two pulleys have radii of 15 cm and 8 cm, respectively. The larger pulley rotates 25 times in 36 sec. Find the angular speed of each pulley in rad per sec. 15. A thread is being pulled off a spool at the rate of 59.4 cm per sec. Find the radius of the spool if it makes 152 revolutions per min.

Solution Section 2.3 – Linear and Angular Velocities

Exercise

Find the linear velocity of a point moving with uniform circular motion, if s = 12 cm and t = 2 sec.

Solution

v s t

2 sec ^ cm

 6 cm / es c

Exercise

Find the distance s covered by a point moving with linear velocity v = 55 mi/hr and t = 0.5 hr.

Solution

svt  55 mihr 0.5 hr 27.5 miles

Exercise

Point P sweeps out central angle  = 12 as it rotates on a circle of radius r with t = 5 sec. Find the

angular velocity of point P.

Solution

t

 ^ 

sec

 ^ rad

2.4 rad / sec

Exercise

Find an equation that expresses l in terms of time t. Find l when t is 0.5 sec, 1.0 sec, and 1.5 sec. (assume

the light goes through one rotation every 4 seconds.)

Solution

/sec 4 2

t sec^ rad

  ^ rad ^ 

/sec 2 rad t

 ^ 

t 2

^ 

l t^100 2 cos  

cos  

 l ^  t

ltt

100 sec 2 cos 2

100  

 

For t = 0.5 sec

 ^  

100 100 100 cos 1 cos^1 2 2 (^4 )

 l       100 2  141 ft

For t = 1.0 sec

 

100 100 cos^0 2

l  (^)    Undefined

For t = 1.5 sec

 ^  

100 100 100 cos 3 cos^31 2 2 (^4 )

l (^)   100 2 141 ft

Exercise

Find the angular velocity, in radians per minute, associated with given 7.2 rpm.

Solution

  1. (^2) min 2 14. 4 45. (^2) min rad rev  rev^   radians  

Exercise

A fire truck parked on the shoulder of a freeway next to a long block wall. The red light on the top of the truck is 10 feet from the wall and rotates through a complete revolution every 2 seconds. Find the equations that give the lengths d and in terms of time.

Solution

t

 ^ 

2 2

^ 

  rad / sec

tan  10^ d

d 10tan  10tan  t

sec  10^ l

l 10sec  10sec  t

Exercise

Suppose that point P is on a circle with radius 60 cm, and ray OP is rotating with angular speed 12 

radian per sec.

a) Find the angle generated by P in 8 sec.

b) Find the distance traveled by P along the circle in 8 sec.

c) Find the linear speed of P in 8 sec.

Solution

a)   t

2

2 1 .8^3 rad

^ ^  

b) srs  (^60)  23   40  cm

c) v st

v  408   5  cm / sec

Exercise

A Ferris wheel has a radius 50.0 ft. A person takes a seat and then the wheel turns 23  rad.

a) How far is the person above the ground?

b) If it takes 30 sec for the wheel to turn 23  rad , what is the angular speed of the wheel?

Solution

a)  23    2  6

cos h^1 r

h 1 (^)  r cos 

h 1 (^) 50cos 6 43.3 ft   Person is 50  43.3 93.3 ft above the ground

b) t  ^ 

2 3 30

rad sec

/ 45 ^  rad sec

Exercise

Tires of a bicycle have radius 13 in. and are turning at the rate of 215 revolutions per min. How fast is the bicycle traveling in miles per hour? ( Hint : 1 mi = 5280 ft.)

Solution

 215 rev^21  revrad^  430  rad / min

vr  13 430  (^)  5590  in / min

60min 1 1 (^5590) min 1 12 5280 in ft mi

v   hr in ft

16.6 mph

Exercise

The pulley has a radius of 12.96 cm. Suppose it takes 18 sec for 56 cm of belt to go around the pulley. a) Find the linear speed of the belt in cm per sec. b) Find the angular speed of the pulley in rad per sec.

Solution

Given : s = 56 cm in t = 18 sec

r = 12.96 cm

a)^56 18 v s 3.1 cm / sec t

b)^ ^ vr 12.963.1^ .24 rad / sec

Exercise

The two pulleys have radii of 15 cm and 8 cm, respectively. The larger pulley rotates 25 times in 36 sec. Find the angular speed of each pulley in rad per sec.

Solution

Given :^25 / sec 36

 times

r 1 (^)  15 cm r 2  8 cm

The angular velocity of the larger pulley is:

^2536^ ti sec^ mes^^21  timerad ^2518  r da / sec

The linear velocity of the larger pulley is:

 ^ / s ce

v r 6 cm

   ^ 

The angular velocity of the smaller pulley is: v (^1) v

 r  r

^ 

(^125) / sec 48 ^  rad

Exercise

A thread is being pulled off a spool at the rate of 59.4 cm per sec. Find the radius of the spool if it makes 152 revolutions per min.

Solution

Given :   152 rev / min v 59.4 cm / sec

r v^1 v  

sec min

cmrev

 ^ ^ 

min sec min sec

rev cm

 rev  rad

3.7 cm

Exercise

A railroad track is laid along the arc of a circle of radius 1800 ft. The circular part of the track subtends a central angle of 40. How long (in seconds) will it take a point on the front of a train traveling 30 mph to go around this portion of the track?

Solution

Given : r = 1800 ft.

180

     ^   rad

v  30 mph

The arc length: 1800  2  400

s r (^) 9 ft

v s^ t s  (^) t   v

400 30

f mi hr

t ^ ^ t

1 3600sec 5280 1

mi ft

hr f tm i hr

^ 

29 sec