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Geometry Homework Solutions: Circles and Shaded Regions, Lecture notes of Calculus

Solutions to various geometry problems involving finding the circumference and area of circles, as well as the area of shaded regions. The problems are presented in terms of different units, including inches, centimeters, and feet. The solutions are given in terms of π and the appropriate units.

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2021/2022

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Section 2.2 Solutions
Homework #1-4: Find the circumference of each circle. Make sure to include the proper units
in your answer. Leave your answer in terms of 𝜋.
1)
𝐶 = 2𝜋𝑟
C = 2𝜋(14𝑚)
Answer: 28𝜋 m
3)
C = 𝜋𝑑
Answer: 16𝜋 𝑐𝑚
5)
P = 2(8cm + 4cm)
P = 2(12 cm)
Answer: 24 cm
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Section 2.2 Solutions

Homework #1-4: Find the circumference of each circle. Make sure to include the proper units in your answer. Leave your answer in terms of 𝜋.

𝐶 = 2 𝜋𝑟

C = 2 𝜋( 14 𝑚)

Answer: 28 𝜋 m

C = 𝜋𝑑

Answer: 16 𝜋 𝑐𝑚

P = 2(8cm + 4cm) P = 2(12 cm)

Answer: 24 cm

  1. Assume opposite sides have equal lengths. Don’t include the 3 cm when finding the perimeter. It is the height, and not one of the sides.

P = 4 cm + 4 cm + 10 cm + 10 cm

P = 28 cm

P = 124 ft + 156 ft + 156 ft

Answer: 436 ft

P = 5 in + 8 in + 3 in + 4 in

Answer: 20 in

Homework: #13 – 24 Find the area of each figure. Use appropriate units.

  1. Assume the lengths are in inches. Area = (^25 𝑖𝑛) 2 (^18 𝑖𝑛)

Area = 225 in^2

A = (10.3 cm)(6.2 cm)

Answer: 63.86 cm^2

Area = (^13.^4 𝑚+^7.^22 𝑚)(^10.^6 𝑚)

Area= 128.26 m^2

Area =

( 20 𝑐𝑚+ 6 𝑐𝑚)( 10 𝑐𝑛) 2

Area = (260 cm^2 )/

Answer: 130 cm^2

  1. (^) Area = (^3 𝑚+^6 𝑚)(^4 𝑚) 2

Area = (36m^2 )/

Answer: 18 m^2

A = (9cm)(16cm)

Answer: 144 cm^2

  1. Assume units are given in inches. A = (8 in)^2

Answer: 64 in^2

35) A = 𝜋( 4 𝑐𝑚)^2

Answer: 16 𝜋 𝑐𝑚^2

  1. Diameter = 6” radius = 3”

A = 𝜋(3")^2

Answer: 9 𝜋 𝑠𝑞𝑢𝑎𝑟𝑒 𝑖𝑛𝑐ℎ𝑒𝑠

  1. Leave your answer in terms of 𝜋. Assume measurements are given in feet.

First calculate the area as if the entire shape was shaded.

Area all shaded = 𝜋( 10 𝑓𝑡)^2 = 100 𝜋 𝑓𝑡^2

Next find the area of the unshaded region.

Area unshaded = 𝜋( 5 𝑓𝑡)^2 = 25 𝜋 𝑓𝑡^2

Finally subtract the amounts.

Answer: 100 𝜋 𝑓𝑡^2 − 25 𝜋 𝑓𝑡^2 = 75 𝜋 𝑓𝑡^2

  1. Use 3.14 for 𝜋. Assume measurements are given in meters.

First calculate the area as if the entire shape was shaded.

Area if entire shape was shaded:

This is a circle with radius 5 m.

Area all shaded = 3.14(5m)^2 = 78.5 m^2

Next find the area of the unshaded region.

Area unshaded = (7m)^2 = 49 m^2

Finally subtract the amounts.

Answer: 78.5 m^2 – 49 m^2 = 29.5 m^2

  1. First calculate the area as if the entire shape was shaded.

Area all shaded = (15mm)^2 = 225mm^2

Next find the area of the unshaded region.

Area unshaded = (5mm)^2 = 25mm^2

Finally subtract the results

Answer: 225 mm^2 – 25 mm^2 = 200 mm^2

  1. First calculate the area as if the entire shape was shaded.

Area all shaded = (30cm)(15cm)= 450 cm^2

Next find the area of the unshaded region.

Area unshaded = (11cm)(22cm) = 242 cm^2

Finally subtract the amounts

Answer: 450 cm^2 – 242 cm^2 = 208 cm^2