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Material Type: Notes; Professor: Maxson; Class: Probability and Statistics; Subject: Mathematics; University: Walters State Community College; Term: Spring 2004;
Typology: Study notes
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(136, 150) for the population mean, μ. Find the margin of error and the point estimate of the mean.
2b. Find the critical tα/2 that corresponds to a 98% degree of confidence. The sample size is 25.
confidence level for the mean life, μ, of all light bulbs of this type.
μ. Find the sample size needed to assure with 68.2% confidence that the sample mean will not differ from the population mean by more than 3 units.
Ch 5 Answers: (Scores calculated using the TI-83 may differ slightly from those using Table A-2due to rounding errors. Some of the answers have been derived from Table A-2; some from the calculator program. You may use either.)
1a. normcdf(180, 225, 200, 20) = .736 1b. normcdf(-1000, 215, 200, 20) = .773 1c. normcdf(240, 1000, 200, 20) = 0. 1d. invNorm(.7, 200, 20) = 210* 1e. normcdf(202, 212, 200, 10/3) = .274 1f. normcdf(198, 1000, 200, 2) =. 2a. P(.67 ≤ z≤1.67) = .9525 - .7486 = .2039 2b. P(z > 1.67) = 1 - .9525 = .0475 2c. P(z < 0.67) =. 2d. P(-0.4 < z < 0.4) = .6554 - .3446 = .3108 2e. x = 75 + (-.44)(15) = 68 2f. x = 75 + (.67)(15) = 85 2g. P(2.33 < z < 9.33) = .9999 - .9901 = .0098 2h. .P(z < -1.8) = .0359 3. normcdf(-1000, 46, 40, 12) =.
Ch. 6 Answers: 1. E = 7; p.e. = 143 2. 2.33 2b. 2.