Review Predict Progeny - Principles of Biology | BYS 119, Study notes of Biology

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Predict Progeny

A/a ; b/b ; C/c ; D/d ; E/e x A/a ; B/b ; C/c ; d/d ; E/e How many of the offspring will be a/a; b/b; c/ c; d/d; e/e One Punnett square per allele

Predict Progeny

From A / a × A / a, one-fourth of the progeny will be a / a. From b / b × B / b, half the progeny will be b / b. From C / c × C / c, one-fourth of the progeny will be c / c. From D / d × d / d, half the progeny will be d / d. From E / e × E / e, one-fourth of the progeny will be e / e.

• (^) ¼ x ½ x ¼ x ½ x ¼ = 1/

What proportion of offspring from that cross will be homozygous at both loci? AaBb X AaBb

• (^) A father is heterozygous for black hair and heterozygous for tongue rolling. Mother is light-haired and heterozygous for tongue rolling. What is the probability of having a light-haired, tongue-rolling child?
• (^) Let Hh = dominant/recessive hair color
• (^) Let Tt = dominant/recessive tongue rolling
• (^) Black hair and tongue rolling are dominant

• (^) In turkeys, dominant gene R produces the bronze color; its recessive allele results in red. Dominant gene H results in normal feathers; its recessive allele results in unwebbed (hairy) feathers. Two bronze turkeys with normal feathers were mated and their offspring were: 8 bronze with normal feathers, three bronze with hairy feathers, two red with normal feathers, and one red with hairy feathers. What were the genotypes of the parents?