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Quiz Solution for Linear Algebra I (Quiz 6) - Finding Adjoint, Inverse, and Solutions, Quizzes of Linear Algebra

The solutions for quiz 6 of the linear algebra i course (1016-331) at rit. It includes the steps to find the adjoint and inverse of a matrix, as well as the use of cramer's rule to find the solution for a system of linear equations.

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2009/2010

Uploaded on 03/28/2010

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1016-331 RIT, 20091 1
Linear Algebra I 1016-331
Quiz 6 Solution
1. Find the adjoint and the inverse of the matrix
A=
a0 0
1a0
0 1 a
.
We compute:
AT=
det ·a0
1a¸det ·1 0
0a¸det ·1a
0 1 ¸
det ·0 0
1a¸det ·a0
0a¸det ·a0
0 1 ¸
det ·0 0
a0¸det ·a0
1 0 ¸det ·a0
1a¸
T
=
a20 0
a a20
1a a2
.
Check:
AAT=
a0 0
1a0
0 1 a
a20 0
a a20
1a a2
=
a30 0
0a30
0 0 a3
.
So the inverse is (for a6= 0):
A1=
1/a 0 0
1/a21/a 0
1/a31/a21/a
.
2. Find the solution of the linear system
x+ 3yz= 4
xy+ 2z= 5
2x+ 2yz= 3.
We compute (Cramer’s rule):
x=
det
4 3 1
51 2
3 2 1
det
1 3 1
11 2
2 2 1
=8
8=1, y =
det
1 4 1
1 5 2
2 3 1
det
1 3 1
11 2
2 2 1
=16
8=2,
z=
det
1 3 4
11 5
2 2 3
det
1 3 1
11 2
2 2 1
=24
8=3.

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1016-331 RIT, 20091 1

Linear Algebra I 1016-

Quiz 6 Solution

  1. Find the adjoint and the inverse of the matrix

A =

a 0 0 1 a 0 0 1 a

We compute:

AT^ =

det

[ (^) a 0 1 a

]

−det

[ 1

0 a

]

det

[ (^1) a 0 1

]

−det

[ 0

1 a

]

det

[ (^) a 0 0 a

]

−det

[ (^) a 0 0 1

]

det

[ 0

a 0

]

−det

[ (^) a 0 1 0

]

det

[ (^) a 0 1 a

]

T

a^2 0 −a a^2 1 −a a^2

Check:

AAT^ =

a 0 0 1 a 0 0 1 a

a^2 0 −a a^2 1 −a a^2

a^3 0 0 a^3 0 0 a^3

So the inverse is (for a 6 = 0):

A−^1 =

1 /a 0 0 − 1 /a^2 1 /a 0 1 /a^3 − 1 /a^2 1 /a

  1. Find the solution of the linear system x + 3y − z = 4 x − y + 2z = 5 2 x + 2y − z = 3.

We compute (Cramer’s rule):

x =

det

det

=^88 = 1 , y =

det

det

=^168 = 2 ,

z =

det

det

=^248 = 3.