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The solutions for quiz 6 of the linear algebra i course (1016-331) at rit. It includes the steps to find the adjoint and inverse of a matrix, as well as the use of cramer's rule to find the solution for a system of linear equations.
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Linear Algebra I 1016-
Quiz 6 Solution
A =
a 0 0 1 a 0 0 1 a
We compute:
det
[ (^) a 0 1 a
−det
0 a
det
[ (^1) a 0 1
−det
1 a
det
[ (^) a 0 0 a
−det
[ (^) a 0 0 1
det
a 0
−det
[ (^) a 0 1 0
det
[ (^) a 0 1 a
T
a^2 0 −a a^2 1 −a a^2
Check:
AAT^ =
a 0 0 1 a 0 0 1 a
a^2 0 −a a^2 1 −a a^2
a^3 0 0 a^3 0 0 a^3
So the inverse is (for a 6 = 0):
A−^1 =
1 /a 0 0 − 1 /a^2 1 /a 0 1 /a^3 − 1 /a^2 1 /a
We compute (Cramer’s rule):
x =
det
det
=^88 = 1 , y =
det
det
z =
det
det