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Questions on Systolic Blood Pressure - Elements of Statistics | MA 116, Exams of Statistics

Material Type: Exam; Professor: Aronne; Class: ELEMENTS OF STATISTICS; Subject: Mathematics; University: Montgomery College; Term: Unknown 1989;

Typology: Exams

Pre 2010

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SYSTOLIC BLOOD PRESSURE
Math 116 – Reviewing for the Final Exam
This is all about Means
Chapter 6 – Normal Distributions
1) For 18-24 year old women, systolic blood pressures (in mm Hg) are normally distributed with
a mean of 114.8 mm Hg and a standard deviation of 13.1 mm Hg.
a) Identify the population and the variable.
Population: 18-24 year old women
Variable: systolic blood pressures (in mm Hg)
b) Identify usual and unusual systolic blood pressures for this population according to the
range rule of thumb.
2 114.8 2 *13.1
[88.6,141]
Any systolic blood pressure reading which is outside of the above interval is considered to
be unusual
c) If one woman from this age group is randomly selected, what is the probability that her
systolic blood pressure is
(i) Between 94 and 142 mm Hg?
94 114.8 142 114.8
(94 142) ( )
13.1 13.1
( 1.59 2.07) 0.9808 0.0559 .9249
P x P z
P z
With calculator: normalcdf(94, 142, 114.8, 13.1) = .9249
(ii) At most 82 mm Hg?
82 114.8
( 82) ( ) ( 2.50) 0.0062
13.1
P x P z P z
With calculator: normalcdf(-10^9, 82, 114.8, 13.1) = 0.0061
(iii) At least 143 mm Hg?
143 114.8
( 143) ( ) ( 2.15) 1 .9842 .0158
13.1
P x P z P z
With calculator: normalcdf(143, 10^9, 114.8, 13.1) = 0.0157
d) Find the two blood pressures having these properties: the mean is midway between them
and 90% of all blood pressures are between them.
There are two scores, one separating the top 5% (with an area of .95 to its left), and
another separating the bottom 5% (with an area of 0.05 to its left). Use the table, from
inside out to find the z scores. The z-scores are – 1.645, and 1.645. Then, use the formula:
114.8 1.645*13.1 93.25
114.8 1.645*13.1 136.35
x z
x z
With calculator: invNorm(0.05, 114.8, 13.1) = 93.25
With calculator: invNorm(0.95, 114.8, 13.1) = 136.35
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Math 116 – Reviewing for the Final Exam This is all about Means Chapter 6 – Normal Distributions

  1. For 18-24 year old women, systolic blood pressures (in mm Hg) are normally distributed with a mean of 114.8 mm Hg and a standard deviation of 13.1 mm Hg. a) Identify the population and the variable. Population: 18-24 year old women Variable: systolic blood pressures (in mm Hg) b) Identify usual and unusual systolic blood pressures for this population according to the range rule of thumb.

[88.6,141]

Any systolic blood pressure reading which is outside of the above interval is considered to be unusual c) If one woman from this age group is randomly selected, what is the probability that her systolic blood pressure is (i) Between 94 and 142 mm Hg?

P x P z

P z

With calculator: normalcdf(94, 142, 114.8, 13.1) =. (ii) At most 82 mm Hg?

P x P z P z

With calculator: normalcdf(-10^9, 82, 114.8, 13.1) = 0. (iii) At least 143 mm Hg?

P x P z P z

With calculator: normalcdf(143, 10^9, 114.8, 13.1) = 0. d) Find the two blood pressures having these properties: the mean is midway between them and 90% of all blood pressures are between them. There are two scores, one separating the top 5% (with an area of .95 to its left), and another separating the bottom 5% (with an area of 0.05 to its left). Use the table, from inside out to find the z scores. The z-scores are – 1.645, and 1.645. Then, use the formula:

x z

x z

With calculator: invNorm(0.05, 114.8, 13.1) = 93. With calculator: invNorm(0.95, 114.8, 13.1) = 136.

Chapter 7 – Section 7.2 – Distribution of Sample Means

  1. For women aged 18-24, systolic blood pressures (in mm Hg) are normally distributed with a mean of 114.8 mm Hg and a standard deviation of 13.1 mm Hg. a) Give the shape, mean and standard deviation of the distribution of sample means for samples of size 36.

X is Normal with^ ^ 114.8^ and  13.

According to the Central Limit Theorem, the distribution of sample means, for samples of size 36, is also normally distributed with

x x

n

b) What is the probability that a sample of 36 women of this age group has a mean systolic blood pressure of at least 121 mm Hg?

P x P z P z

9 13.1^2

With calculator: normalcdf(121, 10 , 114.8, ) = 0.0023~0.002=

c) If the population mean is 114.8, the probability of obtaining a sample of size 36 with a mean of 121 or more is __ 0.002 _____. So, for samples of size 36, about __ 2 __ samples in 1000 will have a sample mean of 121 or more when the population mean is 114.8. Because this event only happens _ 2 __ out of __ 1000 ____ times, we consider it to be usual/ unusual. d) What may this result suggest? If the population mean is 114.8, it’s very unusual to observe a sample of size 36 with a mean of 121 or more. This unusually high result may suggest that “probably” the sample was selected from a population with mean higher than 114.8.

Chapter 9 – Testing a Mean μ

  1. For women aged 18-24, systolic blood pressures (in mm Hg) are normally distributed with a mean of 114.8 mm Hg and a standard deviation of 13.1 mm Hg. A researcher claims that overweight women have a higher systolic blood pressure. Thirty-six women from a group of overweight women from this age group were selected at random and their mean systolic blood pressure was 121 mm Hg. Test the researcher’s claim at the .5% level of significance. (Are you using z or t? Why?)  Set both hypothesis  Sketch graph, shade rejection region, label, and indicate possible locations of the point estimate in the graph. ****You should be wondering: Is x-bar = 121, higher than 114.8 by chance, or is it significantly higher? The p-value found below will help you in answering this.  Use a feature of the calculator to test the hypothesis. Indicate the feature used and the results: Test statistic = p-value = _How likely is it observing an x-bar = 121 or more when you select a sample of size 36 from a population that has a mean μ of 114.8?_* very likely, likely, unlikely, very unlikely _* Is x-bar higher than 114.8 by chance or significantly higher?_**  What is the initial conclusion with respect to Ho and H1?  Write the conclusion using words from the problem

Chapters 8 and 9 – Hypothesis Testing and Confidence Intervals for^  1  2 (Independent Samples)

  1. A researcher wishes to determine whether people with high blood pressure can reduce their blood pressure by following a particular diet. Use the sample data below to test the claim that the treatment population mean  1 is smaller than the control population mean ^2. Test the claim using a significance level of 0.01. Sample size Mean Sample Standard deviation Treatment 85 189.1 38. Control 75 203.7 39. a) Test the claim at the 1% level of significance. (Are you using z or t? Why?)  Set both hypothesis  Sketch graph, shade rejection region, label, and indicate possible locations of the point estimate in the graph. ****You should be wondering: Is the difference between the x-bars lower than zero by chance, or is it significantly lower? The p-value found below will help you in answering this.  Use a feature of the calculator to test the hypothesis. Indicate the feature used and the results: Test statistic = p-value = _How likely is it observing such a difference between the x-bars (or a more extreme one) when the mean of the two populations is equal?_* very likely, likely, unlikely, very unlikely _* Is the difference between the x-bars lower than zero by chance, or is it significantly lower?_**  What is the initial conclusion with respect to Ho and H1?  Write the conclusion using words from the problem b) Construct a 98% confidence interval estimate for the mean difference between the blood pressures of the two groups. What does the interval suggest? (Are you using z or t? Why?)