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Properties of Matter - Lecture Notes - General Chemistry I | CHEM 101, Quizzes of Chemistry

Material Type: Quiz; Professor: Ladogana; Class: GEN CHEMISTRY I; Subject: Chemistry; University: Southeastern Louisiana University; Term: Spring 2011;

Typology: Quizzes

2010/2011

Uploaded on 02/24/2011

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Chemistry 101-01 Monday, February 14,
2011
Chapter 4: Properties of Matter
Main Points
-Endothermic & Exothermic Reactions
-Chemical & Physical Changes
Equation
S . H .=q
M × T
or
S . H .=J
g
S.H. means Specific Heat
Q means heat lost or heat gained (Joules)
M means mass (Grams)
ΔT(Delta Temperature) equation is TT(Delta Temperature) equation is Tfinal –Tinitial = ΔT(Delta Temperature) equation is TT
Example: What is the temperature change when 8.725 g of sodium (Na-1.23
S . H .=J
g
) loses
3138 J of heat? If the initial temperature of the metal was 63.9
, what is the final temperature?
*To make it easier on how to solve the equation make a little information chart with the data that
the problem has given you.
S.H. – 1.23
S . H .=J
g
q- 3138 J
m- 8.72
Tinitial – 63.9
ΔT(Delta Temperature) equation is TT- 293
*How to get ΔT(Delta Temperature) equation is TT with the initial or final temperature?
S . H .
1=q
m × T
(cross multiply)
pf3
pf4

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Download Properties of Matter - Lecture Notes - General Chemistry I | CHEM 101 and more Quizzes Chemistry in PDF only on Docsity!

Chemistry 101-01 Monday, February 14,

Chapter 4: Properties of Matter

Main Points

-Endothermic & Exothermic Reactions

-Chemical & Physical Changes

Equation

S. H. =

q

M ×∆ T

or

S. H. =

J

g ℃

S.H. means Specific Heat

Q means heat lost or heat gained (Joules)

M means mass (Grams)

ΔT(Delta Temperature) equation is TT(Delta Temperature) equation is T final

–T

initial

= ΔT(Delta Temperature) equation is TT

Example: What is the temperature change when 8.725 g of sodium (Na-1.

S. H. =

J

g ℃

) loses

3138 J of heat? If the initial temperature of the metal was 63.

, what is the final temperature?

*To make it easier on how to solve the equation make a little information chart with the data that

the problem has given you.

S.H. – 1.

S. H. =

J

g ℃

q- 3138 J

m- 8.

T

initial

ΔT(Delta Temperature) equation is TT- 293

*How to get ΔT(Delta Temperature) equation is TT with the initial or final temperature?

S. H.

q

m× ∆ T

(cross multiply)

S. H. ×m × ∆T = q × 1

∆ T =

q

SH × M

− 3138 J

J

g ℃

(8.72 g )

*Multiply the 1.23 and 8.72 then divide -3138 which gives you -292.571045 but round and you

get -293. The grams cancel out because picture 8.72 g over one and cancelling g from

g ℃

which leaves you with just

Finishing the ΔT(Delta Temperature) equation is TT equation

-293 ℃ = T

final

T

f

= ΔT(Delta Temperature) equation is TT+T i

T

f

T

f

Chapter 5: Early Atomic Theory and Structure

Main Point

Atoms:

Protons (+)

Neutrons (neutral) *1865 times heavier than

e

Electons (-) *in the nucleus = the center of the atom & high density part of

the atom

Valence

Electrons… High

Energy E

The attraction between

positive charges and

negative charges.

There are 26 protons and 26 electrons.

How many neutrons are there?

56-26=30 neutrons

80

Br

There are 35 protons and neutrons.

How many neutrons are there?

80 – 35= 45 neutrons

*He will always give the Mass number because the periodic table only provides you with the

atomic mass and not the mass number.