Download Problems on Materials Balance with Solutions and more Study notes Materials Physics in PDF only on Docsity!
Lecture 21 Matte smelting: Materials balance Contents: Problem 1 Problem 2 Problem 3 Conclusions
Problem 1 A copper ore has the following proximate analysis ሺ wt. %ሻ: Cuଶ S 20, FeS (^) ଶ 56 ଶ 24 FeO 21% CaO
FeO CaO (^) ଶ % SiO (^) ଶ in slag ൌ 43% All ۽ܑ܁ (^) of ore enters into slag. ۽ܑ܁ (^) balance gives weight of slag ૡ. ܓ. To find weight of limestone we have to calculate CaO. Amount of limestone ൌ 209.3 kg. Matt is a mixture of Cuଶ S FeS. for all calculation purposes. There is no loss of Cu in slag. All copper of
slag. Fe in matte ൌ Total iron െ iron in slag Calculation gives weight of matte ܓ.
roblem
,and SiO. It is smelted in a reverberatory furnace using pure limestone as a flux. The slag has 36% and . Calculate (per 1000 of ore) weight of limestone, slag and matte. Solution: In solving material balance it is importantto have understood the chemistry of matte smelting. In this problem slag consists of 36% and 21% slag will have all SiO in slag .
ore enter into matte. Thereis loss of iron in
P
A copper smelter smelts the ore of the following composition given below in weight percent: Cu 10%, Fe 30%, S 10%, SiO 33%, CaO7%, Al O 4%, H O 6%. Limestone of composition ଷ ଶ its ultimate analysis is ሺwt. %ሻC 82, SiO 8, Al O 5, Fe 2, S 2, H O 1 total sulphur cha oxidiz %) ଶ 9.2, N^ ଶ 78.5.No^ copper^ is^ lost^ in^ slag^ and^ ig
a) The weight of matte and its grade, ion of slag, m sulphur and carbon content,
Matte consists of Cu S FeS. Performing S balance and Cu balance one can find S combined with Cuܵଶ and then amount of FeS Weight of matt ૠ. ܓ and its Grade is ૠ. % Slag consists of SiO (^) ଶ , Al (^) ଶ O (^) ଷ , CaO and FeO, since all Fedoes not enter into matte. One can find weight of each component 845.2 kg. (^2) 5.5% 20.7%
ଶ ଶ ଷ ଶ 94% CaCO and 6%SiO is one‐fifth of the weight of the ore. The coke is 12% of the ore and ଶ ଶ ଷ ଶ.^ During^ smelting^ 25%^ of^ the rged is ed as SO (^) ଶ. The analysis of dry flue gas (In Volume SO (^) ଶ 0.9, CO (^) ଶ 11.4, O nore the flue dust. Determine (for 1000kg ore):
b) Weight and composit c) Volume of gases (dry), calculated fro d) Cubic meter of air. Solution: Basis is 1000kg ore.
ଶ
Weight of slag is SiO 41.6% Al 2 O 3 CaO FeO 32.2%
Volume of gases n performing S and C balance ܛܔܗܕ ܓ .ൌ ૡૡ. ۼ (^) ܕൌ ૢૠ ܚܑ܉ ܛ܍ܞ ܑ ܍܋ܖ܉ܔ܉܊ ^ ,
Problem 3 he proximate analysis of copper concentrate ሺwt. %ሻ^ is as follows:
O
T
Theoretical O (^) ଶ required from air ൌ O (^) ଶ for combustion O (^) ଶ for oxidation െ O (^) ଶ available from Feଶ O (^) ଷ or iron ore. Actual air ൌ 10%of theoretical air. It is advisable that the reader should calculate using the above balances. Acutal amount of air ൌ 2878 mଷ Composition of ga
CO 2
2 2 2
ses
SO 2
H O
N
O
Volume of gases ൌ 2858 mଷ lusion: is lecture techni solve material balance problems in matte smelting is illustrated. There could e other procedure also which may be simpler that what presented here. The lecturer of this course would be extremely happy if the reader innovate any new procedure to solve the problems.
Conc in th que to b
