Answer to HW Problem 21.2 ES205
For ω = 500 rad/s, )50.1500cos(66.0)( += tteo
For ω = 1000 rad/s, )1000cos(10)( tteo=
For ω = 1500 rad/s, )45.11500cos(2.1)( −= tteo
Do you see why this circuit is called a “bandpass filter” ?
00.005 0.01 0.015 0.02 0.025 0.03 0.035 0.04
-10
-5
0
5
10
Time (s)
Input and output (V)
Fig 23.2(a): w = 500 rad/s
Inp ut
Response
00.005 0.01 0.015 0.02 0.025 0.03 0.035 0.04
-10
-5
0
5
10
Time (s)
Input and output (V)
Fig 23.2(a): w = 1000 rad/s
Inp ut
Response
00.005 0.01 0.015 0.02 0.025 0.03 0.035 0.04
-10
-5
0
5
10
Time (s)
Input and output (V)
Fig 23.2(a): w = 1500 rad/s
Inp ut
Response
Note that input and output are identical.