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Math 132 Test 4: Convergence and Divergence of Series and Power Series - Prof. Cathy W. Ca, Exams of Calculus

Math 132 test 4 focusing on determining the convergence or divergence of series and power series using various tests. Students are required to justify their responses and find limits or sums where applicable. Topics covered include the ratio test, alternating series test, limit comparison test, and the first few terms of taylor series.

Typology: Exams

Pre 2010

Uploaded on 08/18/2009

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Math 132 Test 4 4/16/08 Name_____________________________
Calculator–free
1-9. Determine if the following converge or diverge. Justify your response. For the series, mention the test that you
use to determine convergence or divergence. If it is a convergent sequence, give the limit to which it
converges. (6 pts. each)
1.
2
3
3 1
2 1
k
k
a
k k
2.
2
3
4
n
n
a
n
3.
0
3
!
k
kk
4.
1
7
( 1) 1
k
kk
5.
1
cos( )
k
k
7.
2
2
3 1
14 1
n
n
n
a
n n
8.
3k
k=1
k e
9.
2
3
3 1
2 1
k=1
k
k k
10. Determine which series converge. Find the sum of the series where possible. (12)
a)
55
2
5
4
5
8
5
16
...
b)
c)
1
4
2
n
n
11. Find the interval of convergence for the power series:
1
( 1)
4
k
k
k
kx
.(10)
12 a. Find the first three non-zero terms of the Taylor series for f(x) = sin x about
x
. Show your work.
b. Use the first non-zero term of the polynomial to estimate sin 3. (12)
13. a. Find the first four non-zero terms of the Taylor series for f(x) = e3x about x = 0. Show your work.
b. Use your work above to find a polynomial approximation for g(x) = x2e3x.(12)
_______________________________________________________________________________________
1. C to 0; 2. C to 3; 3. C by ratio test; 4. C by alternating series test; 5. D kth term test; 7. D lim n->inf DNE;
8. C ratio test; 9. D limit comparison test compare to sum(1/k,k,0,inf), divergent p-series. 10 all Geometric
(a) a = 5, r = -0.5 converges to 10/3 (b) r = 3, diverges (c) r = ¼, a = 1/16 converges to 1/12
11. (-3, 5) 12a. -1(x-pi)+
3 5
1( ) ( ) / 3! ( ) / 5!x x x
; b) 0.14
13a)
3
2 3
0
1 3 (3 ) / 2! (3 ) / 3! (3 ) / !
k
k
x x x x k
b)
2 3 2 3 4 5
3 4.5 4.5
x
x e x x x x

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Math 132 Test 4 4/16/08 Name_____________________________ Calculator–free 1-9. Determine if the following converge or diverge. Justify your response. For the series, mention the test that you use to determine convergence or divergence. If it is a convergent sequence, give the limit to which it converges. (6 pts. each)

2 3

k k a k k

  1. (^2)

n n a n

0

k k k  

1

k k k  

1 cos( ) kk  

 7.^  

2 2

n n n a n n

3 k k= k e  

2 3

k=1^2 k k k

  1. Determine which series converge. Find the sum of the series where possible. (12) a) (^5) 5 2 5 4 5 8 5 16

     ... b)^0. 2  0. 6  1. 8  5. 4  16. 2 . .. c)^

1 2 4        

n n

  1. Find the interval of convergence for the power series: 1

k k k k x  

 .^ (10)

12 a. Find the first three non-zero terms of the Taylor series for f(x) = sin x about x ^ ^. Show your work. b. Use the first non-zero term of the polynomial to estimate sin 3. (12)

  1. a. Find the first four non-zero terms of the Taylor series for f(x) = e3x^ about x = 0. Show your work. b. Use your work above to find a polynomial approximation for g(x) = x^2 e3x. (12)

  1. C to 0; 2. C to 3; 3. C by ratio test; 4. C by alternating series test; 5. D kth term test; 7. D lim n->inf DNE;
  2. C ratio test; 9. D limit comparison test compare to sum(1/k,k,0,inf), divergent p-series. 10 all Geometric (a) a = 5, r = -0.5 converges to 10/3 (b) r = 3, diverges (c) r = ¼, a = 1/16 converges to 1/
  3. (-3, 5) 12a. -1(x-pi)+ 3 5  1( x   )  ( x  ) / 3! ( x  ) / 5!; b) 0. 13a) 3 2 3 0 1 3 (3 ) / 2! (3 ) / 3! (3 ) k /! k x x x x k

    b) x e^2 3^ x  x 2^  3 x^3^  4.5 x^4^ 4.5 x^5