Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Math 121 Practice Test 4 Hints and Answers, Exams of Algebra

Hints and answers for math 121 practice test 4. It includes solutions for various mathematical problems covering topics like equations, matrices, and algebra. Students can use this document to check their work and understand the solutions.

Typology: Exams

Pre 2010

Uploaded on 08/18/2009

koofers-user-5ef
koofers-user-5ef 🇺🇸

10 documents

1 / 2

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Math 121, Practice for Test 4
Hints and Answers
1. (a) (3,1) (b) (3
5c, c) (c) No solution.
2. Let bbe the rate of the boat, and cbe the rate of the current. This leads to equations
4(b+c) = 120 and 4(bc) = 120. Upon solving, one finds that the rate of the boat is 25mph
and the rate of the current is 5mph.
3. Let xbe the amount invested at 6% and let ybe the amount invested at 6.5%. Then
x+y= 25,000 and .06x+.065y= 1555. Solve these to find that $14,000 was invested at 6%
and $11,000 was invested at 6.5%.
4. (a) (2,3,1) (b) (3c1,2, c) (c) No solution.
5. Solve the equations 2a+b+c= 1, a+ 2b+c= 12 and 3a+ 2b+c= 0 to find that
z=3x+ 2y+ 5.
6. Let n= number of nickels, d=number of dimes and q= number of quarters, and solve the
equations .05n+.1d+.25q= 2, n= 2dand d=q+ 1 to find that there are 10 nickels, 5 dimes
and 4 quarters.
7. (a) (i) k6= 0, (ii) not possible, (iii) k= 0.
(b) k6= 0, (ii) k= 0, (iii) not possible.
8. (a) 3 4 5
158(b)
3 4 17
15 2 19
5 1 2 5
The solutions will be the same as in 1(a) and 4(b).
9. (a) (5 c, 2+3c, 0, c) (b) No solution (c) (0,13,0,5)
10. (a) AB =9 10 10
64 0 (b) Not possible (c) Not possible
(d) 5A3C=5 7 15
1 1 1, (e) Not possible
11. (a) AB is a 3 ×1 matrix, BA doesn’t exist.
(b) Neither multiplications AB nor BA can be performed.
(c) AB is a 5 ×5 matrix, BA is a 3 ×3 matrix.
(d) AB is a 3 ×3 matrix BA is a 2 ×2 matrix.
1
pf2

Partial preview of the text

Download Math 121 Practice Test 4 Hints and Answers and more Exams Algebra in PDF only on Docsity!

Math 121, Practice for Test 4 Hints and Answers

  1. (a) (− 3 , 1) (b) (^35 c, c) (c) No solution.
  2. Let b be the rate of the boat, and c be the rate of the current. This leads to equations 4(b + c) = 120 and 4(b − c) = 120. Upon solving, one finds that the rate of the boat is 25mph and the rate of the current is 5mph.
  3. Let x be the amount invested at 6% and let y be the amount invested at 6.5%. Then x + y = 25, 000 and. 06 x +. 065 y = 1555. Solve these to find that $14,000 was invested at 6% and $11,000 was invested at 6.5%.
  4. (a) (2, − 3 , 1) (b) (3c − 1 , 2 , c) (c) No solution.
  5. Solve the equations 2a + b + c = 1, −a + 2b + c = 12 and 3a + 2b + c = 0 to find that z = − 3 x + 2y + 5.
  6. Let n = number of nickels, d=number of dimes and q = number of quarters, and solve the equations. 05 n +. 1 d +. 25 q = 2, n = 2d and d = q + 1 to find that there are 10 nickels, 5 dimes and 4 quarters.
  7. (a) (i) k 6 = 0, (ii) not possible, (iii) k = 0. (b) k 6 = 0, (ii) k = 0, (iii) not possible.
  8. (a)

[ 3 4 − 5

]

(b)

The solutions will be the same as in 1(a) and 4(b).

  1. (a) (5 − c, −2 + 3c, 0 , c) (b) No solution (c) (0, 13 , 0 , 5)
  2. (a) AB =

[ 9 10

]

(b) Not possible (c) Not possible

(d) 5A − 3 C =

[ − 5 7 15

]

, (e) Not possible

  1. (a) AB is a 3 × 1 matrix, BA doesn’t exist.

(b) Neither multiplications AB nor BA can be performed. (c) AB is a 5 × 5 matrix, BA is a 3 × 3 matrix. (d) AB is a 3 × 3 matrix BA is a 2 × 2 matrix.

1

x − 3 y − 2 z = 6 3 x + y = 2 2 x − 4 y + 5 z = 1

  1. (a)

[ − 3 − 2

]

(b)

 (^) (c) Doesn’t exist

Thus the answers are (a) (− 2 , 0 , 3) and (b) (1, 1 , 1).

  1. a 1 = −1, a 2 = 13 , a 3 = −^15 , a 8 = 151.
  2. a 1 = 5, a 2 = 2(5) = 10, a 3 = 2(10) = 20.

∑^6

i=

(−1)i 2 i^ = −8 + 16 − 32 + 64 = 40.

(b) 8 + 10 + 12 + 14 + 16 + 18 =

∑^9

i=

2 i

  1. (x − y^3 )^6 = x^6 − 6 x^5 y^3 + 15x^4 y^6 − 20 x^3 y^9 + 15x^2 y^12 − 6 xy^15 + y^18
  2. The fourth term of (x + 2y)^12 is

x^9 (2y)^3 = 1760x^9 y^3.

  1. The term of (a − b^3 )^8 that contains b^9 is

a^5 (−b^3 )^3 = − 56 a^5 b^9.