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Practice Exam 2 Answers - General Chemistry | CHEM 112, Study notes of Chemistry

Practice Exam 2 Answers Material Type: Notes; Professor: Dukes; Class: GENERAL CHEMISTRY; Subject: Chemistry and Biochemistry; University: University of South Carolina - Columbia; Term: Spring 2011;

Typology: Study notes

2010/2011

Uploaded on 04/28/2011

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Chap bers [8 ond I Pracfen Exam 2 Chem HI Devkees 1. Circle the best answer for A — J (50 points) ‘A. Far the reaction CN"(aq) + H20(1) # HCN(aq) + OFT (eq) one of the acid-base conjugate pairs is; 1, HCW, Ho Garcnen) 3.90, CN 4. HCN,OH”5.CN, or B, What is the H. no" ie ea in a9 aqueous sstufon baving a omy pam"! concentration af [.0 x107= M? 2 LeMi” = <3 (hot7 Toe Zavie 213x107 3. tax 1o4ae 5.1ax ol _pl (a . fag = C. Ifthe pH of a solution is 4.40: par beg GT a Ge] jj 3.f0rr}= 3.49 1M gti e qos ] 2.{H30"}=25 x10 a 4,(OW}~2.5 10°F 5. pOH~ 1880 ° D. ‘The hydroxide ion concentration in a so! Laan = 2.32%104 432x107 M —5.nane of these E£. — ANolution is found to have a pH of 10.45, What is [H30-17 2910S AE 21Ga 3.28- Ty asx ay 5, cannot be calculated from the tfoemation given xeon F. Which compound is a strong base in water? 1 FQSOy $. none of these 2. NH3 3. HF Chee |e Dukes Yractive Exam 2 Kj for ammonia is 1.8 x 10°, Caleuinte X for the aramonivm ion (ko Rey = {00% = 1.08/07 = hack Ka mat kee soot 242x103 3 Lax 10 1.5.6 10" Solutions are made by combining equal amounts of the following, Which isa buffer? TAH + 0.1 MEF + 0.1.41 Nat 3.0.1 MHF +0,1 NaOH GP NaF + 0.05 HE 5.0.1 MNaF + 0.05. Na* noo “The titration of a weak acid, HA. (Ka = 1.0 x 10°4) with NaOH requires 40.0 mL, to reach the equivalence point. In order to calculate the pH of the system after 20 mL of NaQH is added, the best strateyy is to recognize that the system is 1. asstrong acid 2, a weak acid @ abutter 4. neutral 5. a weak The term “proton acceptor” best defines which af these: 2. Bronsted-Lowry acid @ Bronsted Lowry base 1. Arthenius acid 5. weak acid (15 points). Cafcutate the pOH of a solution made by dissotving 2.0 grams of NaOH (molar mass ~ 40.0 g/mol) in water and diluting to 400 mL. (ail e™ emttie) strony base Nadl saondlin > Net au 0 mebuity of Nook > malanty of OH" > GND LOIN 8 5, a0 acl 40.0 9/mmol Naat mo tale = a eee Ld pol > ~LigfoX] > ~ by (0125) = 40)