Potentially useful data:
t1/2 = 0.693/k
[A]t = - kt + [A]o
ln[A]t = - kt + ln[A]o
1/[A]t = kt + 1/[A]o
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Chem 102 exam values sheet for chem 102 exam
Typology: Exams
2020/2021
Uploaded on 03/03/2021
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Potentially useful data: t1/2 = 0.693/ k [A]t = - k t + [A]o ln[A]t = - k t + ln[A]o