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Portage Learning MATH 110 All Exams statistics questions with complete answers LATEST test Portage Learning MATH 110 All Exams statistics questions with complete answers LATEST test Portage Learning MATH 110 All Exams statistics questions with complete answers LATEST test
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Observation- all the information collected for each element in a study
Element- in a data set, the individual and unique entry about which data has been collected, analyzed and presented in the same manner Variable- a particular, measurable attribute that the researcher believes is needed to describe the element in their study.
An outlier is a value which is out of place compared to the other values. It may be too large or too small compared to the other values
Outliers: 53 63 2333
a) How many were burgers? b) How many were fish?
b.
The z-score is 1, so the data point 57 is 1 standard deviation above the mean.
b) The data point 33 is below the mean. Now use the z-score to determine how many standard deviations 33 is below the mean. We are told that the mean is 49 and the standard deviation is 8. So, the z-score is given by:
The z-score is -2, so the data point 33 is 2 standard deviations below the mean (the negative sign indicates that the point is below the mean).
c) The data point 31 is below the mean. Now use the z-score to determine how many standard deviations 31 is below the mean. We are told that the mean is 49 and the standard deviation is 8. So, the z-score is given by:
The z-score is -2.25, so the data point 31 is 2.25 standard deviations below the mean (the negative sign indicates that the point is below the mean).
d) The data point 79 is above the mean. Now use the z-score to determine how many standard deviations 79 is above the mean. We are told that the mean is 49 and the standard deviation is 8. So, the z-score is given by:
The z-score is 3.75, so the data point 79 is 3.75 standard deviations above the mean.
a) Find the median. b) Find the mode of this set. a) In order to find the median, we must first put the numbers in ascending order:5,
10, 12, 15, 18, 20, 21, 29.
Notice that there are two “middle” numbers, 15 and 18. The median is the average of these two numbers. Median = (15+18)/2 = 16.5.
b) No number occurs more than once, so there is “no mode”.
possible:a) P(412,3)=
b) C(587,585)=
P(A)=.35, P(Bc^ )=.45, P(A∩B)=.25.
Find the following:
a) P(A𝖴B). b) P(Ac^ ). c) P(B). a. For P(A 𝖴 B). Use P(A 𝖴 B)=P(A)+P(B)-P(A∩B). But for this equation, we need P(B) which we can findby using P(B)=1-P(Bc^ ). So, P(B)=1-.45= .55.
b. For P(Ac^ ). Use P(A)=1-P(Ac^ ) which may be rearranged to (Ac^ )=1-P(A).
P(Ac^ )=1-.35=.65.
c. For P(B). Use (B)=1-P(Bc^ ).
probabilities:P(Ac^ )=.50, P(B)=.65,
a) What is (A│B)? b) What is (B│A)?
a. P(Z ≤ 1.27) =0.
b.P(Z ≥ -0.73= 1- P(Z ≤ -0.73)=1- 0.23270=0.
c. P(-0.09 ≤ Z ≤0 .86)= P(Z≤0 .86)- P(Z≤ -0.09)
0.80511-0.46414=.
b) Greater than 3.7 inches? c) Between 3.5 inches and 4.3 inches?
No because the sample has to be at least 30 to use sampling distribution of x̄ or be normally distributed.
Your Answer:
n N ≤ 0.
n 2000 ≤ 0.
n ≤ 0.05(2000)=
Sample size must be less than 100
We calculate the standard deviation of the sample distribution: