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Solutions for the written problems and multiple-choice questions in the physics 101 midterm-i exam for the winter 2024 semester. The solutions cover topics such as constants, equations, conversions, vectors, trigonometric functions, translational kinematics, projectile motion, and circular motion. The document also includes extra credit problems related to these topics.
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1. Your solutions to written problems must have adequate detail, and the answers must contain
appropriate units to get full credit. Read the problems carefully.
2. There are four multiple-choice questions and two numerical problems + one extra credit
multiple-choice question and one extra credit numerical problem.
g = 9.80 m/s
2
Quadratic Equation
Roots of ๐๐ฅ
!
ยฑ
#$ยฑโ$
! #&'(
!'
Vectors
)
Simple trigonometric functions
!
!
sin ๐ =
'
,
cos ๐ =
$
,
tan ๐ =
'
$
Translational Kinematics - 1D
'-,)
) !
#) "
/ !
#/ "
)
0/
'-,)
#- "#
/ !
#/ "
)
0 -
0/
1
)
/
2
)
(t) = ๐ฃ
)
/
2
Special case: Constant acceleration โ 1 - D
)
)
4
!
)
!
3
)
! = ๐ฃ
!
3
3
4
!
)
Projectile Motion
3
3
3
3
4
!
!
)
3
3
3
3
Circular motion
5'
!
5
& 6
! 7
8
!
[IV] ( 8 pts) A careless driver drives his car S through red traffic light and
continues to travel at a constant speed. A police car P starts from rest and
moves with constant acceleration to chase S as shown in the speed( v ) vs.
time( t ) graph. The police car P will catch up with S at:
[a] tc [b] before tc [c] after tc
[IV] (Extra Credit)(5pts) A ball B1 is thrown up from the ground at a velocity, vo , such that it will reach a
maximum height H. Simultaneously, another ball B2 is dropped from rest at height H.
The speed of ball B2 when it hits the ground is:
[a] < vo [b] vo. [c] > vo
The ball B2 takes time T to hit the ground. The time is taken as t=0 when B2 is released. The balls cross paths
at time:
[a] < T/2 [b] T /2 [c] > T /
The balls cross paths at the position above the ground at:
[a] < H /2 [b] H /2 [c] > H /
S
P
v
t t c
o
!
"
[b] (7pts) What is the average speed of the jogger for the trip PabO?
A = 40. 0 (sin 53
o ห i โ cos 53
o ห j ) m = ( 32. 0
i โ 24. 0
j ) m
B = 80. 0 (cos 60
o (^) ห
i + sin 60
o (^) ห
j ) m = ( 40. 0
i + 69. 3
j ) m
C = โ 50. 0 (cos 37
o ห i + sin 37
o ห j ) m = (โ 40. 0
i โ 30. 0
j ) m
ave. speed =
total dist.
time
( 40. 0 + 80. 0 + 50. 0 ) m
= 2. 1 m / s
P
o 120
o
o
x
y
o
A
B
C
a
b
53
$
$
.2+
1.25m
1.5m