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ACS Standard Physical Chemistry Exam with solved Questions.
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ACS Standard Physical Chem Exam Taken Tuesday by 21 students
Score % 33 55. 32 53. 32 53. 32 53. 31 51. 29 48. 28 46. 28 46. 27 45. 27 45. 26 43. 25 41. 24 40. 23 38. 22 36. 21 35. 19 31. 19 31. 18 30. 16 26. 16 26. Average 25.1 41.9 % Last Year 38.6% Nat. Avg. 52 %
December 7, 2017 Total points = 700; Homework is worth 100; midterms = 100 each, and final = The total possible homework points =150 , so: Total % = (total HW/150 * 100 + total exam points )/700 (after including your Final)
Last yearโs letter grades were typical, but could be slightly different this year. T Total % Grade (Estimate) 90-100 A 86-89 A- 80-85 B+ 75-80 B 70-74 B- 68-70 C+ 63-67 C 60-62 C- 50-59 D
A little quiz
System = insulated room with weight lifter
Weight lifter works out and the room heats up
from 20o^ C to 25 o^ C
Are โ U, q, w positive, zero, or negative?
โU = q + w
Adiabatic: q = 0 ; โU = w ; Constant V:
โU = C (^) v (T 2 -T 1 ) if Cv constant For ideal gas the above is always true (even if volume changes)
H = U + PV
For P=Pext = constant and PV work only:
โH = C (^) P (T 2 -T 1 ) if C (^) P constant For ideal gas the above is always true (even if pressure changes)
if isothermal reversible and ideal gas:
Solids and Liquids (volume changes are very small) Cp โ Cv and โH โ โU
T = (^) โซ (^1)
2
dw
w
pv
pv
= โ
= โ (^) โซ
P dV
P dV
ext
V ext
V
1
2
w (^) pv = โ (^) โซ PdV = โ nRT V V V
V (^) ln 2 (^11)
2
T โ =โซ T 2
2
1
2
1
2
1
Sum of fractional changes = natural logarithm
2
1
An integral is just a
At constant T and P, the Gibbs Free Energy is king.
Definition: G = H-TS
โ G = โ H- โ (TS) always true
โ G = โ U + p โ V - T โ S = q - Pext โ V + w (^) useful + p โ V - T โ S
โ G = -T( โ S + โ Ssurr) + w (^) useful
โ G = -T โ S (^) univ + w (^) useful if T and p constant
361 Lec 12 Mon 20sep
(w = - p (^) ext โ V + w (^) useful )