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Determine the formula for a lead(II) acetate hydrate Pb(C2H3O2)2 ... 1.21 g − 0.17 g decrease (water removed) = 1.04 g of the anhydrate (Pb(C2H3O2)2).
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If you are having difficulty please make use of the examples provided in NS F.4 Show your work clearly and carefully on an extra piece of paper so that you can refer to it later to check for mistakes, use for review and/or share your expertise with others.
44 g (%) × 1 mol
1 mol
1 mol
1 mol
1 mol 16 g = 0. 3325 mol
1 mol