






























Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Community
Ask the community for help and clear up your study doubts
Discover the best universities in your country according to Docsity users
Free resources
Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors
An introduction to ordinary differential equations (odes) with a focus on taylor series and the euler method. It covers the expansion of a function using taylor series, the concept of an initial value problem, and the derivation of the euler method. The document also includes examples of applying the euler method to find approximate solutions to odes.
Typology: Slides
1 / 38
This page cannot be seen from the preview
Don't miss anything!
0
0
Noting that
f
is an implicit
function of
y
, we have
( ,
)
x^
y
y
f t y
f^
f dy
y
f^
ff
x
y dx
docsity.com
Similarly
2
2
2
2
(^
)^
(^
)
2
(^
)
3
3
(^
2
)
3(
)(
)
(^
)
xx^
xy^
xy^
yy^
y^
x^
y
xx^
xy^
yy^
y^
x^
y
IV
xxx
xxx
xyy
y^
xx^
xy^
yy
x^
y^
xy^
yy
y^
x^
y
y^
f^
ff
f^
f^
ff
f^
f^
ff
f^
ff
f^
f^
f^
f^
ff
y^
f^
ff
f^
f
f^
f^
ff
f^
f
f^
ff
ff
ff
f^
f^
ff
^
^
^
^
^
^
^
^
^
^
^
docsity.com
Euler method is one of theoldest numerical methodsused for integrating theordinary differential equations.Though this method is notused in practice, itsunderstanding will help us togain insight into nature ofpredictor-corrector method
Consider the differentialequation of first order withthe initial condition
y
( t
) = 0
y
. 0
( ,
)
dy
f t y
dt
Here we use a property that in asmall interval, a curve is nearlya straight line. Thus at (
t^0
,^
y
), 0
we approximate the curve by atangent at that point.Therefore,
0
0
0
0
0
(^ ,
)
0
(^
,^
)
t^ y
y^
y
dy
f t
y
dt
t^ t
^
^
^
^
^
^
That is,
0
0
0
0
Hence, the value of ycorresponding to
t
=
t
1
is
given by
1
0
1
0
0
0
(
)
(^
,^
)
y
y
t^
t^
f t
y
Thus, we obtain ingeneral, the solution ofthe given differentialequation in the form of arecurrence relation
1
(
,^
)
m
m
m
m
y
y
hf t
y
Geometrically, this methodhas a very simple meaning.The desired function curveis approximated by apolygon train, where thedirection of each part isdetermined by the value ofthe function
f
(
t, y
) at its
starting point.
SolutionSince the number of steps arefive, we shall proceed in stepsof (0.1)/5 = 0.02.Therefore, taking step size h
= 0.02, we shall compute the value of
y
at
t^
= 0.02, 0.04, 0.06, 0.08 and 0.
Thus
1
0
0
0
(^
,^
),
y^
y^
hf t
y
^
^
where
0
0 1,^
0
y^
t ^
1
1
0
1
1
0
y^
^
^
Therefore,
2
1
1
1
3
2
2
2
4
3
3
3
5
4
4
4
(^
)^
(^
,^
)^
(^
,^
)^
(^
,^
)^
y^
y^
hf t
y
y^
y^
hf t
y
y^
y^
hf t
y
y^
y^
hf t
y
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
Similarly,