










Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Community
Ask the community for help and clear up your study doubts
Discover the best universities in your country according to Docsity users
Free resources
Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors
Material Type: Assignment; Professor: Buchanan; Class: Ordinary Differential Equation; Subject: Mathematics; University: Millersville University of Pennsylvania; Term: Unknown 2008;
Typology: Assignments
1 / 18
This page cannot be seen from the preview
Don't miss anything!
MATH 365 Ordinary Differential Equations
J. Robert Buchanan
Department of Mathematics
Summer 2008
Recently we have concentrated on finding solutions to second order linear, homogeneous ODEs of the form
L [ y ] = y ′′^ + p ( t ) y ′^ + q ( t ) y = 0.
Today we return to the case of nonhomogeneous second order linear ODEs of the form
L [ y ] = y ′′^ + p ( t ) y ′^ + q ( t ) y = g ( t ),
where p , q , and g are continuous functions on an open interval I.
Theorem If Y 1 and Y 2 are two solutions of a nonhomogeneous second order linear ODE, then their difference Y 1 − Y 2 is a solution to the corresponding homogeneous second order linear ODE. If, in addition, y 1 and y 2 are a fundamental set of solutions to the homogeneous second order linear ODE, then
Y 1 ( t ) − Y 2 ( t ) = c 1 y 1 ( t ) + c 2 y 2 ( t )
where c 1 and c 2 are constants.
Proof.
Theorem The general solution of a nonhomogeneous second order linear ODE can be written as
y ( t ) = c 1 y 1 ( t ) + c 2 y 2 ( t ) + Y ( t )
where y 1 and y 2 are a fundamental set of solutions to the corresponding homogeneous second order linear ODE, c 1 and c 2 are arbitrary constants and Y is some specific solution to the nonhomogeneous second order linear ODE.
The method of undetermined coefficients can be used to find the particular solution when g ( t ) contains polynomials, sines and cosines (but not the other trigonometric functions), exponential functions, or sums and products of these types of functions.
Example Find the general solution to the nonhomogeneous second order linear ODE: y ′′^ + 4 y ′^ + 9 y = t^2.
Example Find the general solution to the nonhomogeneous second order linear ODE: y ′′^ − 4 y = 4 e^2 t^.
Example Find the solution to the nonhomogeneous second order linear IVP:
y ′′^ + 16 y = 5 sin t y ( 0 ) = 0 y ′( 0 ) = 0
Example Find the general solution to the nonhomogeneous second order linear ODE: 4 y ′′^ + y = t^2 + 2 cos 3 t.
Example Find the general solution to the nonhomogeneous second order linear ODE: y ′′^ − 3 y ′^ − 4 y = − 8 et^ sin t.
Example Find the general solution to the nonhomogeneous second order linear ODE:
y ′′^ − 5 y ′^ + 6 y = e^2 t^ ( t + 2 ) cos t.
ay ′′^ + by ′^ + cy = g ( t )
g ( t ) Y ( t ) Pn ( t ) = a 0 + a 1 t + · · · + antn^ tk^ ( A 0 + A 1 t + · · · + Antn ) Pn ( t ) eat^ tk^ ( A 0 + A 1 t + · · · + Antn ) eat
Pn ( t ) eat
sin bt cos bt
tk^ ( A 0 + A 1 t + · · · + Antn ) eat^ cos bt