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mass of one liter of water = 1006 g, Study notes of Chemistry

Union College (Kentucky)Chemistry

Molar mass of urea: (12.01) + 16.00 +2(14.01 + 2(1.008)) = 60.06 g/mol. a. 2.577 m indicates that there are 2.577 mol. of solute per 1000 g of solvent and ...

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Download mass of one liter of water = 1006 g and more Study notes Chemistry in PDF only on Docsity!

3. mass of one liter of water = 1006 g mol Pest,coon = 0.0500%1006 gx =o = 0.838 M=0.838 mol/L 10, Refer to Section 10.1 and Examples 10.4 and 10.5. P Mass Percent Mole Fraction Molality of Solvent Ppm Solute of Solvent 2.877 86.58% 1.340 x 108 0.9556 20.4 45.0 5.50 x 10° 0.731 0.07977 99.5232% 4768 0.9986 12.6 57.0% 4.30 x 10° 0.815 Since these are aqueous solutions, the solvent is water. The solute is urea, CO(NH2)>. Molar mass of urea: (12.01) + 16.00 + 2(14.01 + 2(1.008)) = 60.06 g/mol. 2.577 m indicates that there are 2.577 mol. of solute per 1000 g of solvent and the calculations are based on that ratio. 60.06 < 2.577 mol. x 20:06 8 ee = 1 54 8 9 urea 1 mol. urea eg x 10008 , mol. 0 = 55 49 mol H,0 ikg 1802gH,0 : mass % =— os. 99% = Hee — ge sg0% (1000 g + 154.8 g) 1155 ppm solute = 5482 __y 19° = 1.340 10° (1000 g + 154.8 g) 49 mol. Xu = —95.49mol. 8 0.9556 (55.49 mol. + 2.577 mol.)