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The limit comparison test (lct) is a method used to determine the convergence or divergence of a series by comparing it to a simpler series. The lct, its approach, and provides examples of its application.
Typology: Lecture notes
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Limit Comparison Test
Consider two series
n=
an and
n=
bn with positive terms. Suppose that (^) nlimโโ
an bn
with 0 < C < โ. Then
n=
bn converges, then
n=
an converges.
n=
bn diverges, then
n=
an diverges.
USED: When your given series behaves more like a simpler series, when n is large, but you may not have a direct, obvious, and helpful bound as with the Comparison Test. Also only used for positive termed series.
USED: LCT does not concern itself with which terms are bigger or smaller. LCT only cares if the given terms and the comparison terms are about the same in size, as n gets very big. LCT is the lazy version of comparison, and focuses on the idea that the original series and the (simpler?!) comparison series share the same convergence behavior.
โ (^) polynomial polynomial
NOTE: The order of the stack in the limit of an bn vs. bn an is not so important, because you are
just trying to decide if C is finite and non-zero. It is often easier to put the given terms in the numerator and the comparison terms in the denominator.
NOTE: If C = 0 or C = โ, then you either made a mistake in the Limit computation, OR chose the wrong comparison series to start. Ignore all non-dominant terms as n grows large, and try again.
APPROACH:
EXAMPLES: Determine and state whether each of the following series converges or diverges. Name any convergence test(s) that you use, and justify all of your work.
n=
n^3 + 7n n^9 +
n
Note that
n=
n^3 + 7n n^9 +
n
n=
n^3 n^9
n=
n^6 which is a convergent p-series with p = 6 > 1.
Next, Check: lim nโโ
n^3 + 7n n^9 +
n 1 n^6
= lim nโโ
n^9 + 7n^7 n^9 +
n
n^9
n^9
) (^) = lim nโโ
n^2 1 +
n
(^172)
= 1 which is finite and
non-zero.
Therefore, the O.S. is also Convergent, by Limit Comparison Test (LCT).
n=
n^5 + n + 6 3 n^6 + n^4 + 5
n=
n^5 n^6
n=
n which is a divergent p-series with p = 1.
Next Check: lim nโโ
n^5 + n + 6 3 n^6 + n^4 + 5 1 n
= lim nโโ
n^6 + n^2 + 6n 3 n^6 + n^4 + 5
= lim nโโ
1 + (^) n^14 + (^) n^65 3 + (^) n^12 + (^) n^56
which is finite and
non-zero
Therefore, these two series share the same behavior, and the Original Series is also divergent by Limit Comparison Test (LCT).
n=
n n^6 + 2
n=
n n^6
n=
n^5
which is a convergent p-series with p = 5 > 1.
Next Check: (^) nlimโโ
n n^6 + 2 1 n^5
= lim nโโ
n^6 n^6 + 2 = lim nโโ
1 + (^) n^26
= 1 which is Finite and Non-zero.
Therefore, O.S. is also convergent by LCT. (NOTE: CT would work too)
LAST NOTE: When the Limit C here is Finite and Non-Zero, the test does not directly conclude converge or diverge. LCT says if C is Finite and Non-Zero, then the given series has the same convergence or divergence behavior as its comparison series. The given series does whatever the comparison series does.