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A lab report on the commissioning of a hydraulic power unit. The report outlines the steps to follow, the objective of the lab, and the results obtained. The lab aimed to explore the construction, operation, and operational characteristics of a typical hydraulic power unit. The report provides a detailed account of the process followed and the results obtained, including calculations of theoretical flow rate, drive torque, volumetric efficiency, hydraulic output, horsepower, heat generated, volume of the reservoir, and fluid velocity. The report concludes with a summary of the findings and observations made during the lab.
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301242714
Lab report must be handed in at the beginning of your next lab class. Any late submission will be deducted 10% each business day.
(Last name) (First Name)
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301242714
We were introduced to the practice of using the PDP and ensured its safe use by using Left-handle rule. We investigated the hydraulic supply unit and its action regarding the supply of hydraulic fluid to test motors This lab will provide us with through understanding of taking caution and set up necessary maintenance procedures as industry professional later on OBJECTIVE: The aim of this lab is to explore the construction, operation and operational characteristics of a typical hydraulic power unit. STEPS TO FOLLOW:
301242714
301242714 RESULTS: a. Calculate the Theoretical Flow Rate at 18-degree swash-plate angle Q = Vd * N / 231 Q = (2.06 * 1800) / 231 Q = 16.0519 GPM b. Calculate the drive Torque (TT) at the relief valve setting of 3000 psi TT = P * Vd / 2π TT = 3000 * 2.06 / 6. TT = 984.0764 lb-in c. Observe and record the Actual Flow (Qa) rate at 1800 rpm Qa = 14.5 GPM (given) d. Calculate the volumetric efficiency of this pump V = Qa / Qt V = 14.5 / 16. V = 90.3426% e. Calculate the hydraulic output of the pump at 2000 psi and the Actual Flow Rate (Qa) Qa = N * Vd / 231 14.5 = 1800 * Vd / 231 Vd = 1.8608 in/rev f. Calculate the horsepower that must be produced by the electric motor to produce that maximum hydraulic HP HP = T * N / 63025 HP = 984.0764 * 1800 / 63025 HP = 28.10 HP g. Calculate the heat generated when Qa returns to tank through the relief valve at 2000 psi HP = (Q*P) / 1714 HP = 14.5 * 2000 / 1714 HP = 16.9194 HP h. Calculate the volume of the reservoir V = 46.5 * 26 * 15 V = 18135 in^3 i. Calculate the heat radiated from the surface of the reservoir if the hydraulic fluid temperature is 115 degree F and ambient room temperature is 72 degree F Surface Area = 46.5 * 26 = 1209 in Temp difference (F) = 115 – 72 = 43 HP = .001 * Surface Area * Difference between oil and air temperature HP = .001 * 1209 * 43 HP = 51.987 HP
