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Lab Report on Commissioning of the Power Unit, Assignments of Hydraulics

A lab report on the commissioning of a hydraulic power unit. The report outlines the steps to follow, the objective of the lab, and the results obtained. The lab aimed to explore the construction, operation, and operational characteristics of a typical hydraulic power unit. The report provides a detailed account of the process followed and the results obtained, including calculations of theoretical flow rate, drive torque, volumetric efficiency, hydraulic output, horsepower, heat generated, volume of the reservoir, and fluid velocity. The report concludes with a summary of the findings and observations made during the lab.

Typology: Assignments

2021/2022

Available from 01/06/2023

Hareshjasoliya
Hareshjasoliya 🇨🇦

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Priyank Soni
301242714
1
Course Name: Robo 241 Hydraulics 3
Section: 002
Lab No.: 02
Lab report must be handed in at the beginning of your next lab class.
Any late submission will be deducted 10% each business day.
Student Name: _ _SONI ___ PRIYANK
(Last name) (First Name)
Student No. 301242714
Date: 12th September, 2022
Instructor: PAUL BLIGDON
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301242714

Course Name: Robo 241 Hydraulics 3

Section: 002

Lab No.: 02

Lab report must be handed in at the beginning of your next lab class. Any late submission will be deducted 10% each business day.

Student Name: _ _SONI ___ PRIYANK

(Last name) (First Name)

Student No. 301242714

Date: 12

th

September, 2022

Instructor: PAUL BLIGDON

301242714

COMMISIONING OF THE POWER UNIT

ABSTRACT:

 We were introduced to the practice of using the PDP and ensured its safe use by using Left-handle rule.  We investigated the hydraulic supply unit and its action regarding the supply of hydraulic fluid to test motors  This lab will provide us with through understanding of taking caution and set up necessary maintenance procedures as industry professional later on OBJECTIVE: The aim of this lab is to explore the construction, operation and operational characteristics of a typical hydraulic power unit. STEPS TO FOLLOW:

  1. Switch ON the power supply using PDP
  2. Switch ON the Hydraulic unit
  3. Slide the by-pass valve in non-passing position
  4. Set the flow of fluid to 12 GPM by using swash-plate angle
  5. Observe and note the fluid flow from the flow meter
  6. Note the pressure value from the pressure relief valve on the hydraulic power pack
  7. Calculate and note the efficiency of the piston pump using actual and theoretical flow
  8. Slide the by-pass valve in passing position and unload the load shaft
  9. Switch OFF PDP

301242714

301242714 RESULTS: a. Calculate the Theoretical Flow Rate at 18-degree swash-plate angle Q = Vd * N / 231 Q = (2.06 * 1800) / 231 Q = 16.0519 GPM b. Calculate the drive Torque (TT) at the relief valve setting of 3000 psi TT = P * Vd / 2π TT = 3000 * 2.06 / 6. TT = 984.0764 lb-in c. Observe and record the Actual Flow (Qa) rate at 1800 rpm Qa = 14.5 GPM (given) d. Calculate the volumetric efficiency of this pump V = Qa / Qt V = 14.5 / 16. V = 90.3426% e. Calculate the hydraulic output of the pump at 2000 psi and the Actual Flow Rate (Qa) Qa = N * Vd / 231 14.5 = 1800 * Vd / 231 Vd = 1.8608 in/rev f. Calculate the horsepower that must be produced by the electric motor to produce that maximum hydraulic HP HP = T * N / 63025 HP = 984.0764 * 1800 / 63025 HP = 28.10 HP g. Calculate the heat generated when Qa returns to tank through the relief valve at 2000 psi HP = (Q*P) / 1714 HP = 14.5 * 2000 / 1714 HP = 16.9194 HP h. Calculate the volume of the reservoir V = 46.5 * 26 * 15 V = 18135 in^3 i. Calculate the heat radiated from the surface of the reservoir if the hydraulic fluid temperature is 115 degree F and ambient room temperature is 72 degree F Surface Area = 46.5 * 26 = 1209 in Temp difference (F) = 115 – 72 = 43 HP = .001 * Surface Area * Difference between oil and air temperature HP = .001 * 1209 * 43 HP = 51.987 HP