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Chemistry Lecture 7: Molar Mass, Empirical Formulas, and Chemical Equations, Lecture notes of Organic Chemistry

A portion of a university chemistry lecture from UMass Amherst, covering topics such as molar mass, empirical formulas, and chemical equations. Students are encouraged to continue reading Chapter 3, practice calculating percentages and molecular formulas, and learn about balanced chemical equations and stoichiometry.

What you will learn

  • How do you balance a chemical equation?
  • What is the molar mass of a compound?
  • What is the difference between empirical and molecular formulas?
  • What is stoichiometry and how is it used in chemistry?
  • How do you calculate the percentage composition of a compound?

Typology: Lecture notes

2021/2022

Uploaded on 09/12/2022

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UMass Amherst Biochemistry Teaching Initiative
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Download Chemistry Lecture 7: Molar Mass, Empirical Formulas, and Chemical Equations and more Lecture notes Organic Chemistry in PDF only on Docsity!

ChCh

em 111^ L

t

L

ecture 7

UMass Amherst Biochemistry Teaching Initiative

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  ...

Homework• Continue Reading Chapter 3

OWL

li^

h^

k

  • OWL online homework.

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  ...

Hydrates/ Solvated Crystals^ Often times when you get a compound the solvent will get trapped in thelattice.^ Blue = CoCl

2

Pink = CoCl

6H

O 2

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  ...

Let’s Practice^ Calculate the percentage of nitrogen (by mass) in Ca(NO

)^32

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Let’s Practice^ Anti-freeze, ethylene glycol, is composed of 38.7% carbon, 9.7% hydrogenand 51.6% oxygen by mass. Its molar mass is 62.1 g/mol. What is itsmolecular formula?molecular formula?

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Chemical Equations^ Concise way to represent chemical reactions.2 H (

g)

O (

g)^

Æ

2H O(

l)

2 H

( g) 2

O

( g) 2

Æ

2H

O( 2

l)

“+” = reacts with

reacts with Æ

= produces Left of arrow = reactantsRight of arrow = products

g^

p

Physical State(g)

= gas (l)

= liquid (s)

= solid ( aq)

= aqueous

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Combustion reactions^ Most reaction involve combining O

from air with a reactant. 2

When hydrocarbons are combusted they form CO

+ H 2

O. 2

Suppose we combust (or burn) methanol:CH

OH( 3

l )^

+^

O^2

( g

)^

Æ

CO

( g) 2

H

O( 2

l )

Balance Carbons:

1.^

Balance Carbons: CH

OH( 3

l )^

+^

O^2

( g

)^

Æ

CO

( g) 2

H

O( 2

l )

Balance Hydrogens:

2.^

Balance Hydrogens: CH

OH( 3

l )^

+^

O^2

( g

)^

Æ

CO

( g) 2

2H

O( 2

l )

  1. Balance Oxygens:

yg

CH

OH( 3

l )^

+ 3/2 O

g )

Æ

CO

( g) 2

2H

O( 2

l )

  1. Remove Fractional Coefficients 2 CH

OH( 3

l )^

+ 3O

g )^

Æ

2 CO

( g) 2

4 H

O( 2

l )

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  ...

Chemical EquilibriumChemical Equilibrium –

occurs when opposing reactions are proceeding at

the same rate.N O

Æ

2NO ( )

N^2

O^4

( g

)^

Æ

2NO

( g 2

2NO

g )

Æ

N

O 2

g )

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Aqueous SolutionsElectrolyte –

a substance whose aqueous solutions contains ions and

hence conduct electricity. N^

l^

t^

l t

b t

th t d

t f^

i^

i^

l ti

Non electrolyte -

a substance that does not form ions in solution.

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Ionic Compounds in Water^ Water is a polar solvent.^ NaCl(

s )^

Æ

Na

+^ (

aq

)^

+^

Cl

-^ (

aq

MgCl

( s 2

)^

Æ

Mg

2+^

( aq

)^

+^

2 Cl

-^ (

aq

MgSO

( s 4

)^ Æ

Mg

2+^

( aq

)^

+^

SO

2- 4

aq

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  ...

Solubility

Fig. 3-10, p. 126

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