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Material Type: Assignment; Class: Statistical Applications; Subject: Mathematics; University: Saint Mary's College; Term: Spring 2009;
Typology: Assignments
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Statistical Applications ACTIVITY 6: Inference on two population variances – the F distribution
Why
We continue extending our scope for inference - now we look at the two-population case for inference on variances. We will look only at tests (Do we have evidence of a difference in variances/standard deviations?) and will not consider confidence intervals, which would be very hard to interpret. This topic also introduces a new important distribution – the F distribution, which arises from the ratio of two χ^2 variables.
LEARNING OBJECTIVES
CRITERIA
RESOURCES
PLAN
MODELS
(a) To carry out a test with alternate hypothesis σ^21 > σ^22 , with α =. 05 , if the sample size for population 1 is 31 and for population 2 is 24, we need F. 05 3023 (the last numbers representing the degrees of freedom for numerator and denominator, respectively). So our test criterion will be “Reject H 0 if sample F > 1. 96 ”. If we obtain an F-value 2.50, then our p-value will be between .025 and .01 (because 2.50 is between 2.24 – the critical value for α =. 025 – and 2.62 – the critical value for α =. 01 ).
(b) To carry out a test with alternate hypothesis σ^21 < σ^22 , with α =. 05 , if the sample size for population 1 is 21 and for population 2 is 16, we need F. 95 2015. The table does not include left-side values such as F. 95 , so we must use the conversion formula on the handout: We use the reciprocal and the complementary probability and swap the degrees of freedom: F. 95 2015 =
. 455. So our test criterion will be “Reject H 0 if sample F <. 455 ”. [Left-side critical values for F will typically be less than 1]
(^2) A s^2 B^ with^ df^ numerator^ = 40, df^ denominator^ = 25 III To test at .05 level: Reject H 0 if sample F < F. 975 4025 or if sample F > F. 025 4025 Using table F. 025 4025 = 2. 12 , and from formula F. 975 4025 = (^) F. 0251 25 40 = (^1).^199 =. 503 That is, we will reject H 0 if F <. 503 or if F > 2. 12 IV sample F = 2.^56 2
40 25 =^.^503 V We reject H 0 VI The sample shows, at the .05 level, that there is a difference in variance of temperature between the two thermostats.
EXERCISE
Mean Std Dev n Line A 8.005 0.012 11 Line B 7.997 0.005 16 Do the data give evidence of a difference more variability on line A? What is the p-value?
READING ASSIGNMENT (in preparation for next class) Read Chapter 12 sections 12.1 and 12.3 — inference (tests) for a single distribution (χ^2 goodness of fit)
SKILL EXERCISES:Use your calculator or Minitab for number -crunching [Minitab will carry out hypoth- esis tests when you have actual data to work with] but you have to write the hypotheses and conclusion. p.451 #18–19, p.451 #25, 31