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Material Type: Notes; Professor: Callan; Class: INTRO TO STATISTICAL ANALYSIS; Subject: Economics; University: Clark University; Term: Unknown 1989;
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Econ 160: Introduction to Statistics
Myles J Callan
Spring 2009
The following are the list of some of its important properties of the normal distribution.
The mean, median and mode have the same value and this value is located exactly at the center of the distribution.
The normal curve is symmetrical about the mean.
extended.The tails of the curve do not touch the horizontal axis, and will not touch it no matter how far away they may be
mean.right of the mean is also .5 (50%). That is, we expect 50% of the data to be below the mean, and 50% above theThe total area under the normal curve equals 1. The area to the left of the mean is .5 (or 50%) and the area to the
distribution is infinite.Data that lie beyond three standard deviations from the mean are very rare, although, the range of a true normal
The area under the curve within a certain interval on the horizontal axis is equal to the
probability
that a value selected
at random, from a set of numbers that has this distribution, will lie in that interval.
Additional Properties of the normal curve: The Empirical rules
The empirical rule is given as follows:specific standard deviations from the mean. Given any normal distribution, we can obtain a more exact statement concerning the proportion of the items within
About 68% of the items will lie within the interval from
one
standard deviation
below
the mean to
one
standard
deviation
(^) above
the mean, that is, within the interval
)
(
σ
μ
σ
μ
−
to
About 95% of the items will lie within the interval from
two
standard deviations
below
the mean to
two
standard
deviations
above
the mean, that is, within the interval
)
2
2
(
σ
μ
σ
μ
−
to
Almost all (99.7%) of the items will lie within the interval from
three
standard deviations
below
the mean to
three
standard deviations
above
(^) the mean, that is, within the interval
)
3
3
(
σ
μ
σ
μ
−
to
The empirical rule can be illustrated on a normal distribution.
The
z score (or
standard units
) is a measure of the relative position of a data item in terms of the number of standard
deviations it is from the mean. We can transform each original value into
standard units
, z, by using the formula,
z (^) =
deviation
standard
mean
value
original
z =
s
x
x
−
for
sample data
or
z =
x
for
(^) population data
zzzz
What percent of the scores should fall between 85 and 115?
What percent of the scores should fall between 70 and 130?
What percent of the scores should fall between 55 and 145? = Almost all (99.7%)
First,
draw
the standard normal curve.
Next, we will have to
read
(^) z = 1.86 and z = 1.13 from the standard normal table.
(Area from z = -1.
to z = 1.86) = 0.9372 which implies (Area from z = 0
to z = 1.86) = 0.
(Area from z = -1.
to z = 1.13)
= 0.7416 which implies (Area from z = 0
to z = 1.13)
Answer:
The required Area = 0.4686 - 0.
= 0.0976 or 9.76%
First,
draw
the standard normal curve.
Next, we will have to
read
(^) z = 0.93 and z = 1.59 from the standard normal table.
(Area from z = -0.
to z = 0.93)
= 0.6476 which implies (Area from z = 0
to z = -0.93)
(Area from z = -1.
to z = 1.59)
0.8882 which implies (Area from z = 0
to z = 1.59)
Answer:
The required Area = -0.93 - 1.59 = 0.7679 or 76.79%
(^) x
is normally distributed random variable with
= 40 and
σ
= 15. Find the probability that x is between 35 and
σ Transform 35 and 57 into standard units: Solution: 57
x (^) = 35,
z 35
(^) =
x
x (^) = 57,
z 57 (^) =
Next, we
(^) read
z = 0.33 and z = 1.13 from the standard normal table.
(Area from z = -0.
to z = 0.33) = 0.2586 which implies (Area from z = 0
to z = -0.33) = 0.
Answer:(Area from z = -1.13 to z = 1.13) = 0.7416 which implies (Area from z = 0 to z = 1.13) = 0.
The required Area = 0.1293 + 0.
0.5001 or 50.01%