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Material Type: Assignment; Class: Insurance Law; Subject: Law; University: Boston College; Term: Fall 2008;
Typology: Assignments
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MT 435 Homework Set 7 Due Wednesday, November 19, 2008
Minimize z = 10x 1 + 20x 2 + 15x 3 + 21x 4 + 5x 5 subject to : 3 x 1 − 10 x 2 +6x 3 − 5 x 4 +2x 5 = 600 2 x 1 +x 2 +5x 3 +2x 4 −x 5 = 340
where x 1 , x 2 , x 3 , x 4 , x 5 ≥ 0.
The initial and final tableaus are below; the w row has been suppressed.
x 1 x 2 x 3 x 4 x 5 x 6 x 7 x 6 3 -10 6 -5 2 1 0 600 x 7 2 1 5 2 -1 0 1 340 10 20 15 21 5 0 0 0 x 5 3/16 -7/2 0 -37/16 1 5/16 -3/8 60 x 3 7/16 -1/2 1 -1/16 0 1/16 1/8 80 5/2 45 0 67/2 0 -5/2 0 -
b. What is the optimal solution point to the dual?
3 x 1 − 10 x 2 +6x 3 − 5 x 4 +2x 5 +12x 6 = 600 2 x 1 +x 2 +5x 3 +2x 4 −x 5 +10x 6 = 340
where x 1 , x 2 , x 3 , x 4 , x 5 , x 6 ≥ 0.