Heat Flow-Thermo Propulsion-Assignment Solution, Exercises of Applied Thermodynamics

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“Problem UZ | Solubon | Fall 03 Lo trom GDL, a) 0.4 he - 2457 Whig = [2978.3 } 298, 3 ‘/| (1.356 Wp ug) = [2202 few | b) hect fla Y= 3- Pree BAW heat. capacity of water CC 4,2 T/y% = 400T/ bye Lyprcal body mass m= FO ky (Iss h) us ' ¢ H _ __894.9V rate of temperahwe increase oT = a> F Why wT IA ul n Sag AT yy, = 3K = T bby, tt C) dimmsions, using SI units for example: er br , Vo me, Sem, omm equatou bo 3 e y's ¢, aib> mw fst ~ (by Jn 3) m/s a2 C ~~ ke wm fg C y et a a i = ee 7 | G ts As eon sree fe55 cpechon: M = devi Se Gy pnibn bynthem (KirMnp) nt m By ~ (by WE Gy so [Gy ts dimensionless A) a dimensions scaled by Ye, wih same airflow , J SAS | moto © Hunean body cant tblerte more Yan a few degrees of temperature rise. = 0,03ks BT inase 3°K = i =pat. = af? Ease * = 1000 | = h.7 minutes Loe M= kyem/s? (fore), M~ Wom = by m% (moment) WHE, eae c>se GG, same, docsit com