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PopulationSymbol
Mean
ത^ 𝑋
∑ 𝑋
𝑛^
Median
m
Mode
‐^
Range
R^
Max(X
) – Min(Xi^
)^ i^
‐
Variance
(^2) s
∑
തି^
మ ିଵ
for population
2 , divide by n
(^2)
Standard Deviation
s^
Sqrt(s
2 )^
Pg. 63, Reference book ver. 10 Others: Coefficient of variation (CV), geometric mean, root mean square (RMS)
What is the median of the following data?10, 7, 12, 4, 6, 8a)
4 b)
c)^
8 d)
10 SOLN:Put in ascending (sort) order: 4,6,7,8,10,12If n odd, middle item; if even, average of middle two itemsm = (7+8) / 2 = 7.5 (b)Follow‐up: What is the mode of this data?
ത 𝑋 and S. Based on
Student‐T distribution◦ If standard deviation
^
is unknown:
ത െ 𝑡ഀ𝑋
,ିଵమ^
ௌ ^
൏ 𝜇 ൏ 𝑋
ത 𝑡ഀ
,ିଵమ^
ௌ
◦ If standard deviation
^
is known:
ത െ 𝑍𝑋
ఈ/ଶ
ఙ ^
൏ 𝜇 ൏ 𝑋
ത 𝑍
ఈ/ଶ
ఙ
May also be stated as:
ത േ 𝑡𝑋
ఈ/ଶ
ௌ
=significance level (type 1 error) = 1 – confidence level Z values: use table on page 44, t‐values: use student‐t table pg. 46IEs: also refresh on formulas for CI on difference means and on variance
Pg. 74, Reference book ver. 10
Standard error
Half width
A random sample is selected from a normal distribution with variance 46.12336. If the width of a 95%confidence interval about the sample mean is 4.5, what is the size of the sample?SOLN:Variance is known, so will use Z rather than t: Z
0.05/
= 1.
If width of CI is 4.5, half width is 4.5/2 = 2.25CI halfwidth = Z
/
*
/sqrt(n) , so have 2.25 = 1.96*sqrt(46.12336)/sqrt(n)
Solve for n:
sqrt(n) = 1.96sqrt(46.12336)/2.25n = (1.96^2)46.12336 / (2.25^2) =
^35
Values of Z
a/
CI
Za/
80%
90%
95%
96%
98%
99%
Pg 82‐83 in Ref.handbook ver. 10
𝑥
െ 𝑥
ଶ^ 𝑥ଶ
where measured values xଵ
= 4+/‐0.1 and x 1
= 16+/‐0.5 (+/‐ values 2
indicating standard deviations of each), what is y and the uncertainty of y,
?y
SOLN:y =
4
െ 16
∗ 4 ൌ െ1,
y
=^
భ
𝜎௫ ଶ^ ^ భ
మ
𝜎௫
=^
2𝑥
െ 𝑥ଵ
∗ 0.
ଶ^
0 െ 2𝑥
∗ 𝑥ଶ
ଶ^ ∗ 0.
=^
2 ∗ 4 െ 16
ଶ^ ∗ 0.
0 െ 2 ∗ 16 ∗ 4
∗ 0.
= 68.6y = ‐1,008 +/‐ 68.
𝑃ሺ𝐴ሻ ൌ
Example: Single die toss; let A={2, 4, 6}, so◦ P(A) = 3/6 = 1/2 = 0.5Example: Single coin toss, let A={H}◦ P(A) = 1/2= 0.
P(A) = 1, means event A occurs with certainty.P(A) = 0, means event A is impossible.
P(A
) = 1 – P(A), that is, the probability of not A is simply 1 minus the chance of A happening.
If the events are mutually exclusive (A1, A2,…)
𝑃ሺ𝐴
𝐴ଵ
... ሻ ൌ 𝑃ሺ𝐴ଶ^
ሻ 𝑃ሺ𝐴ଵ
ሻ.. .ଶ^
If the events A
..A 1
n^ are a partition of S,
𝑃ሺ𝐴
𝐴ଵ
⋯ 𝐴ଶ^
ሻ^
ൌ 𝑃ሺ𝐴
ሻ 𝑃ሺ𝐴ଵ
ሻ... 𝑃ሺ𝐴ଶ^
ሻ ൌ 1^
If A and A
^ are complementary,
P(A)+P(A
)=
SOLN:Given P(A)=1/3, P(B)=3/4. Looking for P(A+B).= P(A) + P(B) – P(A,B) = P(A) + P(B) – P(A)*P(B) (since A and B independent)= 1/3 + 3/4 ‐ (1/3)(3/4) = 5/
(d)
A coin is flipped and a 6‐sided die thrown. What is the probability of getting heads and a 5?
a)
1/ b)
1/ c)^
1/ d)
1/
SOLN:12 possible outcomes (2*6), all equally likely. Only one produces the outcome of interest.Pr = 1/12 (d)