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Adiabatic Bomb Calorimetry Introduction Obtaining energy in the form of heat from the combustion or oxidation of thermodynamically unstable (and often kinetically inert) hydrocarbons and its subsequent conversion into useful work, as in cooking or generating electricity or moving a vehicle, must rank as one of the most important applications of thermodynamics in the course of human history. High quality chemical potential energy is constantly being degraded, perhaps doing a little work en route , to useless heat at ambient temperatures. In this experiment, you will determine the molar enthalpy change, Δ C H , for the combustion of naphthalene, C 10 H 8. In general, the total change in enthalpy (Δ H ) is given as the change in internal energy (Δ U ) plus any pressure-volume work [Δ( PV )] that accompanies the process.^1
The use of the "bomb" insures that Δ V = 0. The change in pressure will be calculated from the change in the number of moles of gas, Δ n , in the balanced equation (1), assuming ideal gas behavior for the gases: PV = nRT (4) V Δ P = RT Δ n (5) where Δ n = moles of gaseous products - moles of gaseous reactants. The third term in equation (3) will be Δ n ( RT ), where R = 8.314 J/K mol. Remember that we cannot measure the changes in the energies of chemical systems directly, but rather we observe the release of energy to the surroundings (or absorption of energy from the surroundings) and assume that whatever the surroundings gained is equal to that lost by the system. The heat released in the combustion of naphthalene will be absorbed by the metal bomb and precisely 2.000 liters of water. To insure that we observe all of the released heat (in a temperature rise on a thermometer), the water and bomb are insulated by an air space from the rest of the apparatus. In addition, an effort is made to keep the rest of the apparatus at the same temperature, before and after combustion, as the bomb and its 2.000 liters of water. Under these conditions of no difference in temperature between the bomb and the rest of the apparatus, there will be no heat flow and the experiment will be done under essentially adiabatic conditions.
Figure 1. A schematic diagram of a bomb calorimeter. Procedure The instructions on pp. 165 - 168 of reference 1 will serve as a general guide. The following brief outline will indicate certain important points. You will do one run on a pellet of benzoic acid (BA), a calorimetry standard, to determine the heat capacity of the calorimeter. From the weight of benzoic acid, you can calculate the heat released on combustion from the known Δ C H (BA) and from the observed temperature rise, you can calculate the heat capacity of the bomb and water. Finally you will do one run on a naphthalene (Nap) pellet to determine Δ C H (Nap). When you first arrive in lab, turn on the water temperature controller: i.e. turn on the smaller aluminum box to the right of the big calorimeter. Turn on the main power of the calorimeter, and turn on the cold water supply to the water heater to a slow flow (but more than a trickle). Measure out 2.000 L of water in a volumetric flask (tap water is OK, slightly warm). You want the water temperature to be on scale and at the lower range of the main (front) thermometer of the bomb calorimeter. The samples (about 1 gram for benzoic acid and about 0.5 g for naphthalene) should be pressed into pellets by using the pellet press.
Balance the reaction and calculate V Δ P for this reaction using equation (5). Use room temperature for T. Remember that while Δ n is an integer for the balanced reaction, you must base your calculation on the actual number of moles used in your combustion Δ U (BA) = Δ H (BA) - V Δ P (7) Plot your temperature data against time as indicated below^2 and determine T 1 (final) and T 0 (initial). 0 1 2 3 4 5 6 7 8 9
TBucket/C TJacket/C T i m e / m i n T e m p e r a t u r e / C Maximum Temperature Room Temperature Ignite Charge Initial Test Period Rise^ Period Figure 4. Data taken with Parr Bomb Calorimeter (Summer-90). The heat capacity C (S) of the calorimeter is given as C (S) = – Δ H (BA) – V Δ P + Δ U (Fe) T 1 – T 0
The value of C(S) should be about 10 kJ/K, calculable to four figures.