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A chemistry mock examination focusing on equilibrium constants and gas reactions. It includes multiple-choice questions on calculating equilibrium constants, identifying reaction direction, and interpreting given data. Students are expected to use their knowledge of gas laws and thermodynamics to solve the problems.
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Dr. Wang Chemistry 210, Fall 2006 Mock Examination II
(a) 1 (b) -1 (c) -3 (d) 3
CS 2 (g) + 4H 2 (g) CH 4 (g) + 2H 2 S(g)
(a) 0.11 (b) 0.15 (c) 0.20 (d) 0.27 (e) 0.
B(s) + 3/2F 2 (g) BF 3 (g)
(a) 6.7 x10^48 (b) 6.0 x 10^49 (c) 6.4 x10^50 (d) 6.8 x10^51 (e) 7.7 x10^53
(2) CO 2 (g) + C(s) 2CO (g) โ Hrxn = +172.5 kJ
Hrxn Hrxn Hrxn
(3) H 2 (g) + I 2 (g) 2HI(g) โ = -9.4 kJ
(4) N 2 (g) + O 2 (g) 2NO(g) โ = +181 kJ
(5) N 2 (g) + 2O 2 (g) 2NO 2 (g) โ = +66.4 kJ
(a) 1 (b) 2 (c) 3 (d) 4 (e) 5
H 2 O(g) + CO(g) H 2 (g) + CO 2 (g) + heat
(a) shift in forward direction, Kc will increase (b) shift in reverse direction, Kc will increase (c) shift in forward direction, Kc will decrease (d) shift in reverse direction, Kc will decrease (e) shift in reverse direction, Kc will not change
2NO(g) + 2H 2 (g) N 2 (g) + 2H 2 O(g)
(a) 0.00925 (b) 0.186 (c) 0.282 (d) 0.579 (e) 1.
A (s) 2B(s)
(a) shift in forward direction, Kc will increase (b) shift in reverse direction, Kc will not change (c) shift in forward direction, Kc will decrease (d) shift in reverse direction, Kc will decrease (e) no shift, Kc will not change
(a) 11.09 (b) 2.91 (c) 12.86 (d) 5.
20 .The conjugate acid-base pairs for the reaction: H 2 O(l) + CO 3 2-(aq) HCO 3 - (aq) + OH-^ (aq) are: (a) CO 3 2-/OH-^ and HCO 3 - / OH- (b) H 2 O/ OH-^ and HCO 3 - / CO 3 2- (c) HCO 3 - / CO 3 2-^ and HCO 3 - /H 2 O (d) HCO 3 - /H 2 O and CO 3 2-/ OH-
R = 8.314 J/mol K =0.08206 L atm/mol K
n gas K (^) p Kc RT = ( )โ
For a quadratic equation, ax^2 + bx + c =0, the solutions are
a
b b ac x 2
Answer key is in the next page. DO NOT look at the answer key before you finish your work.