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Molecular Biology Exam: Transcription and Translation in Bacteria and Eukaryotes - Prof. D, Exams of Molecular biology

A molecular biology exam focusing on transcription and translation processes in bacteria and eukaryotes. It includes multiple-choice questions, true or false statements, and short answer questions. Topics covered include the role of transcription factors, rna polymerases, promoters, histones, and gene expression regulation.

Typology: Exams

2011/2012

Uploaded on 05/17/2012

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Molecular Biology Exam 2 Mar 9, 2012 Name:
PLEASE WRITE LEGIBLY. IF THE GRADER CANNOT READ YOUR ANSWER IT WILL BE MARKED WRONG.
1-20. Multiple choice. (20pts/ 1 pt each). Enter the letter of choice that best answers question in the space
provided. (circled sentences will NOT receive credit)
1. A.
2. C.
3 a.
4.d
5.a.
6. a.
7 a.
8 b.
9. a.
10 b.
11. a.
12. d.
13. c.
14. c.
15.d.
16. b.
17 c.
18. a.
19. b.
20. b.
21-30. For each of the following statements, indicate whether the statement is true or false. If the statement is true,
explain. If a statement is false, correct the statement or explain why it is false (2pts each)
correct answer of true with no details – ½ credit
21. TRUE -- a significant distinguishing feature. Euk RNA polymerase must be recruited by transcription factors-
cannot bind promoter on its own / Bacterial RNA pol holoenzyme contains sigma factor
22. False – bacterial mRNA is unstable – typical half life less then 5 min// euk mRNA range in stability but on
average much more stable than bacterial – longer take more time to synthesize/ need to transport to cyto for
translation
23. FALSE: TBP is the positioning factor for transcription initiation by all eukaryotic RNA polymerases – I, II and
III
24 TRUE chromatin remodeling loosens association with histones/ remove histone leading to inc sens
25 TRUE – removal of poly A and cap are steps in the degradation of euk mRNA
Cap protects against 5’ to 3’ exo nuc / poly A protects from 3’ to 5’ exonuclease
26 True – Rho is prokaryotic termination protein . It has ATPase and helicase activities
binds to RNA at rut site and Rho tracks along RNA and when RNA pol pauses at termination helicase activity unwinds
RNA-DNA hybrid to cause termination
27 FALSE – transcription and translation similar 40-45nt/s and 15aa/s (important for some regulatory events)
Transcription is much slower than replication 40 nt /s vs 800bp/s (Rep)
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Download Molecular Biology Exam: Transcription and Translation in Bacteria and Eukaryotes - Prof. D and more Exams Molecular biology in PDF only on Docsity!

PLEASE WRITE LEGIBLY. IF THE GRADER CANNOT READ YOUR ANSWER IT WILL BE MARKED WRONG.

1-20. Multiple choice. (20pts/ 1 pt each). Enter the letter of choice that best answers question in the space provided. (circled sentences will NOT receive credit)

1. A. 2. C. 3 a. 4. d 5. a.

  1. a. 7 a. 8 b.
  2. a. 10 b. 11. a.
    1. d. 13. c. 14. c.
    2. d. 16. b. 17 c.
    3. a. 19. b.
    4. b. 21-30. For each of the following statements, indicate whether the statement is true or false. If the statement is true, explain. If a statement is false, correct the statement or explain why it is false (2pts each) correct answer of true with no details – ½ credit
  3. TRUE -- a significant distinguishing feature. Euk RNA polymerase must be recruited by transcription factors- cannot bind promoter on its own / Bacterial RNA pol holoenzyme contains sigma factor 22. False – bacterial mRNA is unstable – typical half life less then 5 min// euk mRNA range in stability but on average much more stable than bacterial – longer take more time to synthesize/ need to transport to cyto for translation
  4. FALSE: TBP is the positioning factor for transcription initiation by all eukaryotic RNA polymerases – I, II and III 24 TRUE chromatin remodeling loosens association with histones/ remove histone leading to inc sens 25 TRUE – removal of poly A and cap are steps in the degradation of euk mRNA Cap protects against 5’ to 3’ exo nuc / poly A protects from 3’ to 5’ exonuclease 26 True – Rho is prokaryotic termination protein. It has ATPase and helicase activities binds to RNA at rut site and Rho tracks along RNA and when RNA pol pauses at termination helicase activity unwinds RNA-DNA hybrid to cause termination 27 FALSE – transcription and translation similar 40-45nt/s and 15aa/s (important for some regulatory events) Transcription is much slower than replication 40 nt /s vs 800bp/s (Rep)

Bacterial transcription and translation occur at similar rates

28. TRUE most cellular RNA is rRNA which is transcribed by RNA pol I 29. False – centromeres and telomeres constitutive heterochromatin. – permanently condensed Facultative heterochromatin is conditionally heterochromatic (certain cells/ certain times) Mammalian female X chromosome (not every female X chromosome in general) 30. False- sporulation involves alternative sigma factors 31. (2pts) Polysomes are mRNA with attached ribosomes. These cannot occur during eukaryotic transcription because eukaryotic transcription takes place in nucleus and translation (ribosomes) is in the cytoplasm 32 (4pts) Which gene (tesA or tes B) do you expect to be more efficiently transcribed? Why? tesA more efficiently transcribed -- -10 box is closer to consensus (given that rest of promoter is identical) What is the role of the -10 region? Involved in formation of open complex 33 (2pts) DNA about 200bases (140-200bp) histone core octamer – 2 copies each of H2A, H2B, H3, H 34 (2pts) Polymerase transcribes a Different set of genes with different sigman factors

  1. (4pts)R is Recognition helix – (specific contacts between the side chains of the helix and bases in the DNA) The lambda and lac repressor bind DNA as dimers
  2. (2pts)Centromere is highly repetitive AT rich DNA alphoid DNA – thousands of copies of (171bp) repeat
  3. (2pts) Centromere function: Attachment of microtubules point where two sister chromatids held together region which forms kinetochore 38 (2pts) yeast centromere and other eukaryotic centromeres Similar function 39. (2pts) In cells that lack telomerase – telomeres shorten at each round of replication (until too short and die) 40. (2pts) insulator prevents (blocks) the spread of heterochromatin
  4. (2pts) Constitutive heterochom: always condensed – all cells Facultative heterochom: condensed in some cells and decondensed in others (where genes are expressed)

Bonus (2pts) No activation because: GR without hormone is Sequestered in the cytoplasm.- (bound to hsp90) Answer such as because it can’t bind DNA is not acceptable. It could bind DNA but is excluded from the nucleus.