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Material Type: Exam; Class: Intro Quant Reasoning; Subject: Mathematics; University: University of Utah; Term: Spring 2008;
Typology: Exams
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MATH 1030-008 Spring 2008
Absolute Change = N V − RV = 2500 − 1000 = 1500
Relative Change =
= 1.5 or 150 %
Let S be the original number of students, S 1 be the number of students after year 1, and S 2 be the number of students after year 2. We have
S 1 = (100 − 15)% of S = 0. 85 × S and S 2 = (100 + 8)% of S 1 = 1. 08 × S 1.
Therefore, S 2 = 1. 08 × S 1 = 1. 08 × (0. 85 × S) = 0. 918 × S.
This tells us that the percentage change is
(0. 918 − 1) × 100 = − 8 .2 %
We need to compare the two temperatures. So, we need to either convert the Monday temperature to Celsius or the Tuesday temperature to Fahrenheit.
From the above calculations, we can see that it was hotter on Tuesday.
as a pet. The following results were obtained.
15 have a cat, but not a dog or a tarantula. 22 have a dog, but not a cat or a tarantula. 13 have a tarantula, but not a cat or a dog. 8 have a cat and dog, but not a tarantula. 45 have a dog and a tarantula, but not a cat. 5 have a tarantula and a cat, but not a dog. 8 have none of the three pets.
How many people have all three pets? How many people have a dog or a tarantula?
See Handout.
Premise: Everyone who gets their flu shot does not get the flu. Premise: Jackie got her flu shot. Conclusion: Jackie did not get the flu.
See Handout.
a) What is your speed in feet per minute? b) How long will it take you (in minutes) to travel 1000 feet?
a) First, recall that 5280 ft = 1 mile and 60 min = 1 hr. From these conversion factors, we can convert the 5 miles per hour as follows.
Speed = 5 miles hr
5280 ft 1 mile
1 hr 60 min
440 ft min
b) For this part, recall that distance = speed × time. This tells us that time = distance/speed. Therefore,
Time = distance speed
1000 ft 440 ft per min ≈ 2 .273 min