Free Energy and Equilibrium: Calculating Delta G under Non-Standard Conditions, Lecture notes of Chemistry

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Free Energy and Equilibrium

Back to LeChat’s…three scenarios: I. II. III. Correcting for non-standard conditions  G ° Keq

(kJ/mol)

10 200

 G

ln Q

a. If ( 1 ) is at equilibrium, calculate Kp.

What is the free energy change for the process under the conditions: T = 25 °C, P (N 2 ) = 0.870 atm , P (H 2 ) = 0.250 atm, and (NH 3 )= 12.9 atm?

What about at 875 °C in a 5.00 L flask

containing 0.100 mol of each gas?

What happens to free energy as a

reaction proceeds??

A ⇌ B

G A

G B

If we start with pure A,

Turning some A into B

Real Example:

H 2 ( g ) + I 2 ( g ) ⇌ 2 HI ( g )

Q = Keq =